Question
A gaseous mixture consists of 16g of helium and 16g of oxygen. the ratio Cp/Cv of the mixture is
(1) 1.59
(2) 1.62
(3) 1.4
(4) 1.54
Joshi sir comment
16 gms He = 4 mole, 16 gms O2= 1/2 mole
so total freedom n = [4(3) + 1/2(5)] / [4 + 1/2] = 3.22222 here 3 and 5 are freedoms for mono and di atomic gases
so γ = 1 + 2/3.2222222 = 1.621