Question
A BALLOON WITH ITS CONTENTS WEIGHING 160N IS MOVING DOWN WITH AN ACCELERATION OF g/2 ms-2. THE MASS TO BE REMOVED FROM IT SO THAT THE BALLOOON MOVES UP WITH AN ACCELERATION g/3 ms-2 IS
Joshi sir comment
according to the given conditions
for downward journey 160-R = (160/g)g/2 = 80 so R = 80
now after removing m kg the new equation
R - [160/g - m]g = [160/g - m]g/3
put the value of R and get m