Question
a body is projected vertically upward with speed 32 m/s. total time taken in its complete journey is
suppose it travelled h height thus from bottom to top it will covered h height in time t1 & at top its vel will be zero thus from eqn v= u-gt => 0= 32- 10t u can find t1= 3.2s , same time particle will take in downward journey so total time = 6.4 sec.
This answer is given by sarika and is correct answer, we made some modifications only
Read 2 Solution.
suppose it travelled h height thus from bottom to top it will covered h height in time t1 & at top its vel will be zero thus from eqn v= u-gt => 0= 32- 10t u can find t1= 3.2s , now during its downward motn again it will cover h distance thus by using eqn v2-u2=2as, u can find final vel by putting u=0 now find t2 & add t1 and t2 to get the final ans
3.2 sec