the amount of U-235 required per day to run a power house of capacity 50 MW (efficiency of nuclear reactor 75%. Assume energy liberated by fission of 1 U-235 atom is 200 Mev) is

(a) 15.8gm

(b) 28.1gm


(d) none of these

Joshi sir comment

let x gm is required

then according to the given condition 

(x/235)*6.023*1023*200*106*1.6*10-19 = 50*106*86400


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