Question
the amount of U-235 required per day to run a power house of capacity 50 MW (efficiency of nuclear reactor 75%. Assume energy liberated by fission of 1 U-235 atom is 200 Mev) is
(a) 15.8gm
(b) 28.1gm
(c)21.1gm
(d) none of these
Joshi sir comment
let x gm is required
then according to the given condition
(x/235)*6.023*1023*200*106*1.6*10-19 = 50*106*86400
solve