Question

which is the 4 digit number whose second digit is thrice the first digit and 3'rd digit is sum of 1'st and 2'nd and last digit is twice the second digit.

Joshi sir comment

let the 4 digit number is 1000a+100b+10c+d

then according to the given condition b=3a, c=a+b, d=2b

so c=4a, d=6a and b=3a

on putting all the values we get number = 1000a+100(3a)+10(4a)+6a = 1346a

on putting a =1, number = 1346

Read 2 Solution.

its 1346

RSIVA 11 year ago is this solution helpfull: 1 0

1346

ASHUTOSH RANJAN 11 year ago is this solution helpfull: 0 0

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