Question
which is the 4 digit number whose second digit is thrice the first digit and 3'rd digit is sum of 1'st and 2'nd and last digit is twice the second digit.
Joshi sir comment
let the 4 digit number is 1000a+100b+10c+d
then according to the given condition b=3a, c=a+b, d=2b
so c=4a, d=6a and b=3a
on putting all the values we get number = 1000a+100(3a)+10(4a)+6a = 1346a
on putting a =1, number = 1346
Read 2 Solution.
its 1346
RSIVA 12 year ago
is this solution helpfull: 1 0
1346
ASHUTOSH RANJAN 12 year ago
is this solution helpfull: 0 0