Question
a particle is projected at an angle of 60 degree with the horizontal at a speed of 30m/s. the time after which the speed of the particle remain half of the initial speed is
Joshi sir comment
intial speed = 30 m/s
at top point speed = 30 cos60 = 15
so answer will bo half time of flight
Solution by Joshi sir.
intial speed = 30 m/s
at top point horizontal speed = 30 cos60 = 15
vertical component will be 0
so speed = 15 m/s
so answer will bo half time of flight
= usinθ/g