Question
the frequency of radiation emitted when the electron falls n=4 to n=1 in a hydrogen atom will be (given ionisation energy of H =2.18*I0-18 J/atom )
ans=3.08*1015
Joshi sir comment
for n = 1 E = 2.18*10-18
for n = 4 E = 2.18*10-18/16
so hν = 15*2.18*10-18/16
so ν = 15*2.18*10-18/16*6.634*10-34
so ν = 3.08*1015