Question
A hydrogen like system has ionisation enthalpy 11808KJ/mol. find the no of protons in the nucleus of the system?
Joshi sir comment
A hydrogen like system has ionisation enthalpy 11808KJ/mol
on converting it into eV we get [11808*1000]/[6.023*1023*1.6*10-19] = 122.53 eV
now formula for this energy is [-Z2/n2]13.6 eV
for n = 1, Z will be 3