Question

The enthalpy of nuutralisation of  a strong acid HA and weaker acid HB by KOH are -13.7 and -12.7 kcal/eq. When one equivalent of KOH is added to a mixture containing 1 eq of HA amd HB ; the enthaply change was -13.5 kcal. In what ratio is thge base distributeed between HA and HB ?

Joshi sir comment

let x in HA and 1-x in HB

so according to the given condition -13.7x-12.7(1-x) = -13.5

solve

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