Question
1-In the following hypothetical reaction A + 3B --------------
2C + D, initial moles of A is twice that of B. If
at equilibrium moles of B and C are equal, % of B reacted is?
Joshi sir comment
A + 3B ---------> 2C + D
1 1/2 0 0
1-x 1/2-3x 2x x
according to the given condition 1/2 - 3x = 2x
so 1/10 = x
so 3x = 3/10
so % = 0.3*100/0.5 = 60
Read 1 Solution.
1-In the following hypothetical reaction A + 3B --------------
2C + D, initial moles of A is twice that of B. If
at equilibrium moles of B and C are equal, % of B reacted is?
Answer:40%
SUNNY KUMAR 11 year ago
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