Question
A body is projected with a velocity 'u' making an angle α with the horizontal. Its velocity when it is perpendicular to the initial velocity vector is:
A. ucotα B. utanα C. usinα D. ucosα
Joshi sir comment
component of gravity perpendicular to the final direction is gsinθ so by equation
v=u+at
0 = u -gsinθt
so t = u/gsinθ
now along final direction v = 0+gcosθt on putting the value of t we get v = gcosθu/gsinθ = ucotθ
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ans ucot@ ,
ARECA NUT 11 year ago
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