# 17 - Kinetic Theory of Gases Questions Answers

Joshi sir comment

Joshi sir comment

Constant b is associated to volume correction so its value be less for molecule of smaller volume.

Joshi sir comment

### Two flasks of equal volume connected by narrow tube(of negligible volume) are at 300K and contains 0.7 mole of H2(.35 mole in each flask) at 0.5 atm.One of the flask is then immersed in a bath kept at 400k while the other remains at 300K. Caculate the final pressure and the number of moles of H2 in each flask.

Asked By: ABHISHEK PAHI
Joshi sir comment

by gas eq.  PV/nT = constant

so 0.5*2V/0.7*300 = PV/n1400 + PV/n2300        (1)

no. of moles are also constant

so 0.7 = n1 + n2

similarly by gas eq.

PV = n1R400                      for first flask

PV = n2R300                      for second flask

now solve

## Calculate molecular diameter of  He from its Van der Waal's constant  b=24ml/mole.

Asked By: ABHISHEK PAHI
Joshi sir comment

b = 4Vwhere V is volume of 1 mole particles

so 24*10-6 cm3/mole = 4*[4πr3/3] cm3/mole

now solve

The Total energy of one mole of an ideal monoatomic gas at 300K is____.

Asked By: ABHISHEK PAHI
Joshi sir comment

= 3RT/2

differential form of boyle's law

Asked By: SWATI KAPOOR
Joshi sir comment

dV/dP = -V/P

the de- Broglie wavelength of a tennis ball of mass 200g and moving with a speed of 5m/h is of the order

10-20  , 10-30 ,   10-40

Asked By: SWATI KAPOOR
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Joshi sir comment

λ = h/mv

put values and solve but first convert all values in MKS

6.3g of hydrated oxalic acid is treated with M/20 Mg(OH)2. The volume of Mg(OH)2 used for complete neutralisation is

Asked By: SWATI KAPOOR
Joshi sir comment

gm eq of oxalic acid = 6.3/63 = 0.1

gm eq of Mg(OH) = (1/20)*2*V

now compare the two

In a hydrogen atom electron moves around the circular orbits of radii R and 4R respectively. The ratio of the time taken by them to complete one revolution is

Joshi sir comment

mv2/r = kqe/r2

so v2α 1/r

or (r/t)2α 1/r

or t2 α r3

now solve

There is two atoms of 'P' in one molecule of a compound. If the compound contains 27.93% of phosphorus, the compound will be......

(atomic mass of P = 31)

Asked By: SWATI KAPOOR