# 4 - Redox Reactions and n factor Questions Answers

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Joshi sir comment

In first case reactions involved are

In second case reaction involved is${\mathrm{As}}_{4}{\mathrm{O}}_{6}+4{{\mathrm{I}}_{3}}^{-}\to {\mathrm{As}}_{4}{\mathrm{O}}_{10}+12{\mathrm{I}}^{-}$Now solve

inform if any issue

Balance

KMnO4+H2SO4+H2S -> K2SO4+MnSO4+S+H2O

Joshi sir comment

THE E0 VALUES OF FOLLOWING REDUCTn  Rxn  R GIVEN

Fe 3+ (aq ) + e ----> Fe3+ (aq)  E0= 0.771V

Fe2+(aq)  + 2e----> Fe (s) E0 =0.447V

WHAT WILL BE THE FREE ENERGY CHANGE FOR D Rxn ?

Fe3+(aq) + 3E----> Fe(s)

ans +11.87kJ/MOL.

Asked By: SARIKA SHARMA
Joshi sir comment

Third reaction is the sum of 1st and 2nd so energy of 3rd will be the sum of energies of 1st and 2nd.

delta G = n1FE1 + n2FE2 = 1F(0.771) + 2F(0.447) = F(0.771+0.894) = 1.665F = 1.665*96368 = 160452.7 J = 38203.03 cal = 38.20303 cal

so total energy of the reaction

Fe3+(aq) + 3e- -------> Fe(s) is 38.203 cal

and value of n = 3 so per mole energy = 38.203/3

oxide of E react with KOH & give compd like KMnO4 WHAT IS THE FORMULA OF OXIDE OF E

EO

E2O3

E2O7      OR ANY OTHER ANS (& IF ANY OTHER ONE THEN GIVE THAT ANS WITH SOLn)

Asked By: SARIKA SHARMA
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Joshi sir comment

2 EO2 + 4 KOH + O2 → 2 K2EO4 + 2 H2O
and
3 K2EO4 + 2 CO2 → 2 KEO4 + 2 K2CO3 + EO2

so oxide will be EO2