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13 - Atoms and molecules Questions Answers

Chemistry >> General Chemistry >> Atoms and molecules Medical Exam

THE FIRST EMISSION LINE IN THE ATOMIC SPECTRUM OF HYDROGEN IN BALMER SERIES APPEAR AT ?

ANS 5R/36cm-1

Asked By: SARIKA SHARMA
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Joshi sir comment

for balmer series of hydrogen atom 

 1/λ = R ( 1/22  -   1/32)     

solve for λ

Chemistry >> General Chemistry >> Atoms and molecules Medical Exam

IF n & l are principle & azimuthal quantum no. respectively then expression for calculating total no. of e- in any energy level is?

summation from l=0 to n-1 (2(2l+1)) HOW

Asked By: SARIKA SHARMA
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Joshi sir comment

for nth level values of l will be 0, 1,  2,  3, 4, 5, .....................(n-1) 

for l = 0   means s subshell no. of electrons = 2      = 2(2*0+1) 

for l = 1 means p subshell no. of electrons = 6        = 2(2*1+1)

for l = 2 means d subshell no. of electrons = 10      = 2(2*2+1)

similarly for others 

 

Chemistry >> General Chemistry >> Atoms and molecules Medical Exam

the ques which i have already submitted i.e. d ques in which we have to find min transitional energy in terms ofRH , IS THE ANS IS RH. PLS AGAIN TELL THAT SOLn so that i can understand more easily

Asked By: SARIKA SHARMA
is this question helpfull: 4 1 submit your answer
Joshi sir comment

for max transitional energy we will use 

E = hcRH {1/12  - 1/∞2}

so E will be proportional to RH

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