- Organic Chemistry
- Aldehydes and Ketones
- Alkyl Halides, Alcohols and ethers
- Amines and other nitrogen compounds
- Aromatic Chemistry
- Carbohydrates, Amino acids, protein, Vitamin and Fat
- Carboxylic acids and its derivatives
- Chemistry in daily life
- General Mechanism in organic compounds
- Hydrocarbons
- Nomenclature and isomerism
67 - General Chemistry Questions Answers
6.3g of hydrated oxalic acid is treated with M/20 Mg(OH)2. The volume of Mg(OH)2 used for complete neutralisation is
gm eq of oxalic acid = 6.3/63 = 0.1
gm eq of Mg(OH)2 = (1/20)*2*V
now compare the two
In a hydrogen atom electron moves around the circular orbits of radii R and 4R respectively. The ratio of the time taken by them to complete one revolution is
mv2/r = kqe/r2
so v2α 1/r
or (r/t)2α 1/r
or t2 α r3
now solve
The equivalent weight of N2 and NH3 for the given reaction respectively will be (if M1 and M2 are molar masses of NH3 and N2)
N2 => NH3
e w of N2 = 28/6
e w of NH3 = 17/3
The density of a gas is 3.80 g/l at STP. Calculate its density at 27°C and 700 torr pressure.
P = dRT/M
for first condition
760 = 3.8R273/M
and 700 = dR300/M
divide and get the answer
Two oxides of a metal M contain respectively 22.53% and 30.38% of O2. If the formula of first oxide is MO, the formula of second oxide is
(a) M2O3 (b) MO3 (c) M2O (d) M2O4
M O
77.47 22.53
m w M 16
formula for first oxide is MO
so 77.47/M = 22.53/16
so M = 77.47*16/22.53 = 55
M O
69.62 30.38
m w 55 16
so M:O = 69.62/55:30.38/16 = 1.27:1.90
1.9/1.27 = 1.5
so formula will be M2O3
if radius of first bohr orbit of hydrogen atom is X, then de Broglie wavelength of electron in 4 th orbit is
radius of fourth orbit = 16X
now put 2πr = 4λ
Is there is any relation between bond order and bond angle
no
the correct increasing order of lattice energy of the above compounds is - AlF3 , Al2O3 and AlN
AlF3 5924 kJ/mol
Al2O3 15916 kJ/mol
AlN 9506.8 kJ/mol
24.5g KClO3 heated to give O2, which is allowed to react completely with H2 to form H2O. This H2 comes from Zn and H2SO4 reaction. The amount of Zn required for the purpose is
2KClO3 ----------------------> 2KCl + 3O2
3O2 + 6H2 --------------------> 6H2O
6Zn + 6H2SO4 -------------------> 6ZnSO4 + 6H2
so 2 mole KClO3 ----------------------------- 6 mole Zn
now solve
If the potential energy of hydrogen electron is -3.02eV in which of the following energy levels is electron present =
1st , 2nd , 3rd or 4th
Energy = -13.6/n2 , Potential Energy = -27.2/n2
for n = 3 we get -3.02
in this answer infinite is zero potential energy level