22 - Organic Chemistry Questions Answers

Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.

 

Asked By: KRISH
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Asked By: PRIYANSHU SINGH
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What products will be formed and why? Why would EtMgBr attack on a particular side of cyclic ester?
Asked By: LUFFY
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Joshi sir comment

Why does

Zn + HCl reduce aldehydes and ketones to alcohols while

Zn - Hg amalgam + HCl reduce aldehyde and ketones to alkanes

Asked By: LUFFY
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Joshi sir comment

 H₂+ Pd + C  Reagent ... It reduces a C=C to C-C ... Is this addition syn or anti?

Asked By: LUFFY
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Joshi sir comment

It is syn reagent

It is m-CPBA
Asked By: LUFFY
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Joshi sir comment

mCPBA is a good oxidizing agent for alkenes and ketones. Here both are present, in that case mCPBA attacks on alkene. Alkene on OMe side is more reactive. So make epoxide this side. Remember also that stereo nature is not changed in this reaction means cis be cis and trans be trans. 

Is the H on B-carbon sterically hindered ?

Asked By: LUFFY
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Joshi sir comment

Steric hindrance is a relative word, so is compared between two carbons.

Tertiary carbon is always more sterically hindered than primary,

so β carbon is more hindered than α in this compound

In 1 and 2 ... are the two isomers geometrical iso or optical iso?
Asked By: LUFFY
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Joshi sir comment

1. It is cis-trans pair (no chiral carbon atom so no optical isomerism)

2. has chiral carbon atom so case of optical isomerism, mirror images so dextro and laevo

CH3-(CHBr)-CH2-CH3   +  Na  --------> ?

 

 

Asked By: AAYUSH TANEJA
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Joshi sir comment

in presence of ether it is Wurtz reaction and as obvious many products will be formed.

Major product will be CH3-CH2-CH(CH3)-CH(CH3)-CH2-CH3

Arrange The Following in increasing order of reactivity towards nucleophilic substitution and give reason :

CH3F , CH3Cl , CH3Br , CH3I  .

 

Asked By: AAYUSH TANEJA
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Joshi sir comment
Better the leaving group the compound contains, more reactive the compound will be 
towards the nucleophilic sustitution.
Order of decreasing reactivity. 
 
CH3I > CH3Br > CH3Cl > CH3
 

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