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7 - Thermodynamics and Thermochemistry Questions Answers

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry Medical Exam

ΔHf  C2H4 = 12.5 kcal

Heat of atomization of C = 171 kcal  

Heat of atomization of H = 52.1 kcal  

Bond energy C−H = 99.3 kcal .

What is C=C bond energy?

Asked By: SWATI KAPOOR
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Joshi sir comment

2 heat of atomization of C + 4 heat of atomization of H - 4 bond energy of C-H - 1 bond energy of C=C = heat of formation of C2H4

2*171 + 4*52.1 - 4*99.3 - x = 12.5

solve

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry Medical Exam

Integral enthalpy of soln of KCl , when 1 mole of it is dissolved in 20 mole water is +15.90kJ . When 1 mole of it is dissolved in 200mole water  dH =15.58kJ. Calculate enthalpy of hydratn or dilutn ??

 

ans is 2.68kJ

Asked By: SARIKA
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Joshi sir comment

Integral enthalpy 

please check this word if wrong submit the correct question again

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry IIT JEE

show that (du/dv)s=T-sdp

 

Asked By: KARTHIKCHEMIST
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Joshi sir comment

question is incorrect 

because (du/dv)s represents pressure and T is temperature

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry IIT JEE

why heat of an ideal solution is taken as zero ?

Asked By: H. SHASHANK KUMAR
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Joshi sir comment

because in ideal solution there is no interaction between the two liquids present in the solution

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry IIT JEE

The enthalpy of nuutralisation of  a strong acid HA and weaker acid HB by KOH are -13.7 and -12.7 kcal/eq. When one equivalent of KOH is added to a mixture containing 1 eq of HA amd HB ; the enthaply change was -13.5 kcal. In what ratio is thge base distributeed between HA and HB ?

Asked By: H. SHASHANK KUMAR
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Joshi sir comment

let x in HA and 1-x in HB

so according to the given condition -13.7x-12.7(1-x) = -13.5

solve

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry Medical Exam

16 kg oxygen gas expands at STP isobarically to occupy double of its original volume. The work done during the process is 244 kcal. HOW????????

Asked By: AVANTIKA PURI
is this question helpfull: 5 4 read solutions ( 3 ) | submit your answer
Joshi sir comment

W = PdV = nRdT = (16*1000/32)*(8.31/4.18)*273 

now solve

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry Medical Exam

the heat of formation of MgO, Al2O3, , And SiO2 Are -692, -1676, -911 kJ/mol . most stable oxide is

A) MgO

B) Al2O3

C) SiO2

D) can't be predicted

Asked By: SARIKA
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Joshi sir comment

Al2O3

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