214 - Chemistry Questions Answers

 Joshi sir comment

Constant b is associated to volume correction so its value be less for molecule of smaller volume.

Considering the electrode potential of hydrogen to be zero, electrode potential of fluorine is +2.87 volt. It implies that fluorine is best oxidising agent, and thus it oxidises oxygen in the given reaction. Besides it low bond energy of fluorine is also a factor for its dissociation and participation in the reaction. 

Amount of DCl = 4 milimole

Amount of NaOD = 8 milimole

After reaction of acid and base 

Amount of NaOD remaining = 4 milimole

Total volume = 100 ml = 0.1 lit

$$\begin{gathered} so \left[OD\right] =4*{10}^{-3}/0.1=4*{10}^{-2} \left(1\right) \\ Given pD = 13.6 \\ so \log \left[D^{+}\right] =-13.6= \overline{14}.4 \\ \Rightarrow \left[D^{+}\right] =2.5*{10}^{-14} \left(2\right) \\ Now solve \end{gathered}$$

It is syn reagent

mCPBA is a good oxidizing agent for alkenes and ketones. Here both are present, in that case mCPBA attacks on alkene. Alkene on OMe side is more reactive. So make epoxide this side. Remember also that stereo nature is not changed in this reaction means cis be cis and trans be trans. 

Sharing is the case applicable for the atoms of same electronegativity, thus by sharing electrons (charges) atoms make their orbital configurations stable according to the rules defined for stability.