216 - Chemistry Questions Answers

 Inertness of BrO₄^- at room temperature stands in sharp contrast to its high thermodynamic oxidizing power, which is greater than that of any other oxohalogen ion that persists in aqueous solution. The oxidation potential is
BrO₄^-+ 2H⁺ + 2e^- -------> BrO₃^- + H₂O                              E =  +1.853 V

(1.201 V for ClO₄^- and 1.653 V for IO₄^-)

For this it is necessary to remember all the bond energies

x % HNO₃ --------------------- 100 + (18/108)*x % of fuming HNO₃

so 18x/108 = 10 

or x = 60 %

question is not appropriate because for given K_w , [H⁺] will be 10^-3 and max. pH will be 6 and the question is asking about a solution of pH 7.5 which is out of limit 

but if it is considered as a correct question then answer will be (ii)

 N₂   +    O₂   =    2NO 

  1                       1                       0

  1-x                    1-x                  2x

so by formula K_c = (2x)² / (1-x)(1-x)

now solve for x

SO₂Cl₂ = SO₂ + Cl₂

_{100               0           0}

_{20                  40       40}

_{2 atm             4 atm   4 atm}

now calculate K_p 

N₂ (g) + 3H₂ (g) =  2NH₃ (g)

0.2          0.6                0

0.2-x       0.6-3x         2x

according to the given condition 4x = 0.8*40/100 = 0.32

so x = 0.08

now solve

A (g) + B (g) = C (g)

  1         1.5        2

1-x      1.5-x     2+x

according to the given condition 2+x = 0.5 so x = -1.5

now calculate K_c

Ag₂CrO₄ -------------> 2Ag + CrO₄

s                                            0                  0

                                              2s                 s

so K_sp = (2s)² s = 4s³

now solve   

Please submit complete question, K_a should be given with percentage of ionisation