213 - Chemistry Questions Answers

Chemistry >> General Chemistry >> Redox Reactions and n factor IIT JEE

Both are separate questions....How to know what reaction is going to occur in each?

Asked By: LUFFY

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Joshi sir comment

In first case reactions involved are $Reduction of {Fe}^{+ + +}, {Fe}^{+ + +} \to {Fe}^{+ +} Titration step, 6 {Fe}^{+ +} + K_{2} {Cr}_{2} O_{7} \to 6 {Fe}^{+ + +} + 2 {Cr}^{+ + +} By using titration reaction, solve the question$

In second case reaction involved is ${As}_{4} O_{6} + 4 {I_{3}}^{-} \to {As}_{4} O_{10} + 12 I^{-}$ Now solve

inform if any issue

Chemistry >> Organic Chemistry >> Nomenclature and isomerism IIT JEE

In 1 and 2 ... are the two isomers geometrical iso or optical iso?

Asked By: LUFFY

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Joshi sir comment

1. It is cis-trans pair (no chiral carbon atom so no optical isomerism)

2. has chiral carbon atom so case of optical isomerism, mirror images so dextro and laevo

Chemistry >> General Chemistry >> Redox Reactions and n factor IIT JEE

Balance

KMnO4+H2SO4+H2S -> K2SO4+MnSO4+S+H2O

Asked By: LUFFY

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Joshi sir comment

Chemistry >> Physical Chemistry >> Solutions Board Exam

Q.WRITE CELL RECTION OF THE FOLLOWING- .{1} ZN | ZN²⁺|| cu²⁺ |cu {2} PT {H₂} | HCL || CL₂{PT}

Asked By: PINKU UMAR

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Joshi sir comment

Zn -----------> Zn⁺⁺ + 2e^-

Cu⁺⁺ + 2e^------------> Cu

H₂ --------> 2H⁺ + 2e^-

Cl₂+ 2e^- --------> 2Cl^-

Chemistry >> Inorganic Chemistry >> Peridic table IIT JEE

If each orbital can hold a maximum of three electrons , then the number of elements in 9th period of periodic table

Asked By: VAIBHAV GUPTA

is this question helpfull: 8 3 read solutions ( 1 ) | submit your answer

Joshi sir comment

3/2 times of the previous number of elements

Chemistry >> General Chemistry >> Atoms and molecules IIT JEE

At 752 mm Hg of total Pressure and 301 K Temperature 150 ml H₂ is produced and collected over the water, when current is passed through acidic water for 1 hour. How many Amp. current should have passed? ( at 301 K temperature, The pressure of water is 28 mm Hg )

A) 0.320 A

B) 310 A

C) 321 A

D) 0.305 A

please mention correct answer.

Asked By: BONEY HAVELIWALA

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Solution by Joshi sir

by formula PV/T = constant

(752-28)*150/301 = 760*V/273

solve for V, this will be the equivalent volume at STP

now convert this volume in gm by the formula 2V/22400

then finally m = zit, where

z = 1/96500

solve it for i

Chemistry >> Physical Chemistry >> Solutions Medical Exam

one molar solution of sulphuric acid is equal to 2N. how???

sir as we know for sul.acid n factor = 2

so normality will be = 2xM thus M = N/2

but ans is 2N so plz give account of it .

Asked By: SARIKA

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Joshi sir comment

molarity = 1

and N = nM = 2(1) = 2

hence it is clear

Chemistry >> General Chemistry >> Kinetic Theory of Gases AIEEE

Two flasks of equal volume connected by narrow tube(of negligible volume) are at 300K and contains 0.7 mole of H2(.35 mole in each flask) at 0.5 atm.One of the flask is then immersed in a bath kept at 400k while the other remains at 300K. Caculate the final pressure and the number of moles of H2 in each flask.

Asked By: ABHISHEK PAHI

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Joshi sir comment

by gas eq. PV/nT = constant

so 0.5*2V/0.7*300 = PV/n₁400 + PV/n₂300 (1)

no. of moles are also constant

so 0.7 = n₁ + n₂

similarly by gas eq.

PV = n₁R400 for first flask

PV = n₂R300 for second flask

now solve

Chemistry >> General Chemistry >> Kinetic Theory of Gases Board Exam

Calculate molecular diameter of He from its Van der Waal's constant b=24ml/mole.

Asked By: ABHISHEK PAHI

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Joshi sir comment

b = 4V, where V is volume of 1 mole particles

so 24*10^-6 cm³/mole = 4*[4πr³/3] cm³/mole

now solve

Chemistry >> General Chemistry >> Kinetic Theory of Gases Board Exam

The Total energy of one mole of an ideal monoatomic gas at 300K is____.

Asked By: ABHISHEK PAHI

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Joshi sir comment

= 3RT/2

213 - Chemistry Questions Answers

Calculate molecular diameter of He from its Van der Waal's constant b=24ml/mole.

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