217 - Chemistry Questions Answers

It is syn reagent

mCPBA is a good oxidizing agent for alkenes and ketones. Here both are present, in that case mCPBA attacks on alkene. Alkene on OMe side is more reactive. So make epoxide this side. Remember also that stereo nature is not changed in this reaction means cis be cis and trans be trans. 

Sharing is the case applicable for the atoms of same electronegativity, thus by sharing electrons (charges) atoms make their orbital configurations stable according to the rules defined for stability.

Steric hindrance is a relative word, so is compared between two carbons.

Tertiary carbon is always more sterically hindered than primary,

$so \beta carbon is more hindered than \alpha in this compound$

In first case reactions involved are$$\begin{gathered} \mathrm{Reduction} \mathrm{of} {\mathrm{Fe}}^{+++}, {\mathrm{Fe}}^{+++}\to {\mathrm{Fe}}^{++} \\ \mathrm{Titration} \mathrm{step}, 6{\mathrm{Fe}}^{++}+{\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7\to 6{\mathrm{Fe}}^{+++}+2{\mathrm{Cr}}^{+++} \\ \mathrm{By} \mathrm{using} \mathrm{titration} \mathrm{reaction}, \mathrm{solve} \mathrm{the} \mathrm{question} \end{gathered}$$

 In second case reaction involved is${\mathrm{As}}_4{\mathrm{O}}_6+4{{\mathrm{I}}_3}^{-}\to {\mathrm{As}}_4{\mathrm{O}}_{10}+12{\mathrm{I}}^{-}$Now solve

inform if any issue

1. It is cis-trans pair (no chiral carbon atom so no optical isomerism)

2. has chiral carbon atom so case of optical isomerism, mirror images so dextro and laevo

Zn                  ----------->   Zn⁺⁺   +   2e^-

Cu⁺⁺ + 2e^-   ----------->   Cu

H₂  -------->  2H⁺  +   2e^- 

Cl₂ + 2e^-      -------->  2Cl^-

3/2 times of the previous number of elements

by formula PV/T = constant

(752-28)*150/301 = 760*V/273

solve for V, this will be the equivalent volume at STP

now convert this volume in gm by the formula 2V/22400

then finally m = zit, where 

z = 1/96500

solve it for i