24 - Co ordinate Geometry Questions Answers

Consider a branch of the hyperbola x²-2y²-2√2x-4√2y-6=0, with vertex at the point A. Let B be one of the end points of its latus rectum .If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is??????
Asked By: SNEHA ARORA 3 year ago
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If angle between two st. Lines represented by 2x^2+5xy+3y^2+7y+4=0 is arc tan(m) then find m.
Asked By: HARSH 4 year ago
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if the point P ( x,y) be equidistant from the points A( a+b,a-b) and B( a-b,a+b) then:

a) ax=by

b) bx = ay

 

Asked By: SUMIT SAURAV 5 year ago
is this question helpfull: 4 8 read solutions ( 2 ) | submit your answer

SCRA 2013

Suppose the figure 'A' is obtained by joining the points (2,2), (6,5), (10,2). The horizontal line Segment end Points (3,4) and (x,y). What is the value of x & y?

1. x=7 & y= 4

2.x=3 & y= 4

3.x=9 & y= 4

4.x=6 & y= 4

Asked By: GAUTAM SAGAR 5 year ago
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Tangents are drawn to the circle x^2 + y^2=12 at the points where it is met by the circle x^2 +y^2 - 5x + 3y - 2=0.Find the point of intersection of these tangents.

Asked By: SUSHOVAN HALDAR 5 year ago
is this question helpfull: 17 9 submit your answer
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

sovle the two eqs for x and y,

method : 

x^2 + y^2=12 

on putting this in 2nd eq. we get -5x+3y = -10 so x = (3y+10)/5

so [(3y+10)/5]+ y2= 12

now get y then x, then get the tangents in the first circle and then intersection point of the tangents.

ƒ(x)=|x-2| and g=ƒoƒ so g'(x)=.......? ; 2<x<4

Asked By: BONEY HAVELIWALA 5 year ago
is this question helpfull: 4 7 read solutions ( 1 ) | submit your answer
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

for 2<x<4,   f(x) = x-2

so g(x) = f(x-2) = x-2-2 = x-4

so g'(x) = 1 

ƒ(x)=3|2+x| so ƒ'(-3)=? ,if its -3 , how?

Asked By: BONEY HAVELIWALA 5 year ago
is this question helpfull: 5 2 read solutions ( 1 ) | submit your answer
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

ƒ(x)=3|2+x|

for x>-2,  f(x) = 3(2+x)  so  f'(x) = 3 

for x<-2, f(x) = -3(2+x) so f'(x) = -3

A(3,4) and B is a variable point on the line |X| = 6. Also, AB ≤ 4. Then the number of positions of B with integral co-ordinates is:

(a)5  (b) 6 (c) 10 (d) 12

 

Asked By: GAUTHAM GANESH 5 year ago
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Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

by diagram (6,4),(6,3),(6,2) are points having AB<4 besides it two upside points are also there by symmetry not shown in diagram. These points are (6,5) and (6,6)

Total no. of points = 5

If|z| =1and w=z-1/z+1.thenRe(w)is:
Asked By: SHEIKH SARTAJ 6 year ago
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if the latus rectum of any ellipse makes an angle of 90* <ninety degrees> at its centre then what will be its eccentricity?

Asked By: RATTAN SINGH 6 year ago
is this question helpfull: 7 0 read solutions ( 1 ) | submit your answer

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