# 18 - Co ordinate Geometry Questions Answers

**Asked By: LUFFY**

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$Letthelinesinthepairare{m}_{1}x-y=0and{m}_{2}x-y=0\phantom{\rule{0ex}{0ex}}Findperpendicularsfrom({x}^{,},{y}^{,})onlinesandcalculatetheirsum\phantom{\rule{0ex}{0ex}}Useformulae{m}_{1}+{m}_{2}=-\frac{2h}{b}and{m}_{1}{m}_{2}=\frac{a}{b}\phantom{\rule{0ex}{0ex}}$Inform for any issue

### Tangents are drawn to the circle x^2 + y^2=12 at the points where it is met by the circle x^2 +y^2 - 5x + 3y - 2=0.Find the point of intersection of these tangents.

**Asked By: SUSHOVAN HALDAR**

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sovle the two eqs for x and y,

method :

### x^2 + y^2=12

on putting this in 2nd eq. we get -5x+3y = -10 so x = (3y+10)/5

so [(3y+10)/5]^{2 }+ y^{2}= 12

now get y then x, then get the tangents in the first circle and then intersection point of the tangents.

ƒ(x)=|x-2| and g=ƒoƒ so g'(x)=.......? ; 2<x<4

**Asked By: BONEY HAVELIWALA**

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**read solutions ( 1 ) | submit your answer****Joshi sir comment**

for 2<x<4, f(x) = x-2

so g(x) = f(x-2) = x-2-2 = x-4

so g'(x) = 1