# 11 - Differentiation Questions Answers

ROORKEE 1988 MATHS ME EK QUESTION H SECOND ORDER DERIVIATIVE KA...PLEASE ANYONE CAN PROVIDE ME THE SOLTN

**Asked By: SUFIYAN KARIM**2 year ago

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**Asked By: RIYA GUPTA**3 year ago

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a non zero polynomial having real coefficients satisfy the relation f(x)=f'(x)f''(x) then find f'''(x)

a1/2

b1/3

c1/4

d1/6

**Asked By: AMRITA**3 year ago

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**Asked By: ASHIT MAHAJAN**5 year ago

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d/dx((1+x^2+x^4)/(1+x+x^2))=ax+b

then a=?, b=?

**Asked By: RAJIV**5 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

1+x^{2}+x^{4} = (1+x+x^{2})(1-x+x^{2})

now solve

x(√1+y)+y(√1+x)=0,prove that dy/dx=-1/(1+x)^{2}

**Asked By: SANDEEPNALCO**6 year ago

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A tarder buys goods at 19% off the list price he wants to get a profit 20% after allowing a discout of 10%. At what % above the list price should he marks the goods.

Answers -

1) 4%

2) 6%

3) 8%

4) none

**Asked By: UTKARSH BHARDWAJ**6 year ago

**Solved By: SAGAR**

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**Asked By: GAURAV MAHATE**6 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

since first one is a straight line so at every point only one tangent is possible so it is differentiable

but second one which is modulus has a sharp turn at x = -5/2 so two tangents at x = -5/2 are possible so is not differentiable.

lim ∑ ^{n}_{r=1 }1/n e^{r/n }n tends to infinity.

**Asked By: NIKHIL VARSHNEY**6 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

limn->∞ ∑_{r=1}^{n }e^{r/n}/n

This question is related to definite integration, consider 1 and divide it into n parts, upto nth part total value = r/n is equivalent to x and 1/n is dx

so question will be

_{0}∫^{1} e^{x}dx

now solve it

if f(X)=xlxl then find f^{-1}(x) can you please explain me the meaning and use of sgn

**Asked By: NIKHIL VARSHNEY**7 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

f(x) = x|x| => f(x) = -x^{2} for negative real values of x and f(x) = x^{2} for positive real values of x

so f^{-1}(x) = -√|x| for negative real values and = +√|x| for positive real values of x