# 10 - Sequence and Series Questions Answers

if 16 ,20 ,16 ,d are in AGP then d can be

Asked By: RUTVIK 4 year ago
Maths >> Algebra >> Sequence and Series Board Exam

If a,b,c,d are in H.P.  then prove that a+d>b+c

Asked By: TRILOK PATIL 5 year ago
Maths >> Algebra >> Sequence and Series Board Exam
Plz gave me solution to question in NCERT class 11 mathematics :-miscellaneousPlz gave me solution to question in NCERT class 11 mathematics :-miscellaneous exercise on chapter 9, question no. 19 on pg-200
Asked By: ASHIT MAHAJAN 6 year ago

the sum of the series 1+ 1.3/6 + 1.3.5/6.8 + ... to infinity

Asked By: H. SHASHANK KUMAR 7 year ago

if |x|<1, then find the sum of the series x/(1-x2) +x2/(1-x4) +x4/(1-x8) +............ to infinite terms

Asked By: TREEK 7 year ago
Maths >> Algebra >> Sequence and Series Engineering Exam

2,4, 8, 16, 32, 64, ....,

Asked By: NITESH CHANDU BHASARKAR 7 year ago
Maths >> Algebra >> Sequence and Series Engineering Exam
Asked By: DINESH KHANNA 7 year ago
Maths >> Algebra >> Sequence and Series Engineering Exam

what is the sum of all even integers between 99 and 301?

A)40000

B)20000

C)40400

D)20200

Asked By: DINESH KHANNA 7 year agoSolved By: RSIVA

The sum of three positive real numbers x, y and z is 9. If the largest positive difference between any 2 of the 3 numbers is 5 and these 3 numbers are in arithmetic progression then the product of these 3 numbers will be what .please tell me.

Asked By: S.NANDHINI 8 year ago

let the numbers are a-d, a, a+d

then according to the given condition    a-d+a+a+d = 9   so  3a = 9   so a = 3

and [a+d]-[a-d] = 5   so 2d = 5 so d =5/2

now solve

The AM of two positive numbers a & b exceeds their GM by 3/2 & the GM exceeds the HM by 6/5 such that a+b= α , |a-b|=β , then which of them are correct,

1) α + β² = 96            2) α + β² =74          3)α²+β = 234         4)α²+β = 84

Asked By: AMIT DAS 8 year ago

(a+b)/2 = √ab + 3/2                   (1)                        or         a+b = 2√ab + 3

√ab      = 2ab/(a+b)  +  6/5       (2)                        or         5(a+b)√ab  =  10ab + 6(a+b)

on solving these 2 we get               5[2√ab + 3]√ab = 10ab + 6[2√ab + 3]

or               10ab + 15√ab  =  10ab + 12√ab + 18

or                3√ab = 18     or      ab = 36          and      a+b = 15 = α

so a-b = √(225 - 144)     =    √81     =     9 = β