# 10 - Sequence and Series Questions Answers

if 16 ,20 ,16 ,d are in AGP then d can be

**Asked By: RUTVIK**3 year ago

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If a,b,c,d are in H.P. then prove that a+d>b+c

**Asked By: TRILOK PATIL**4 year ago

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**Asked By: ASHIT MAHAJAN**5 year ago

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the sum of the series **1+ 1.3/6 + 1.3.5/6.8 + ... to infinity**

**Asked By: H. SHASHANK KUMAR**6 year ago

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if |x|<1, then find the sum of the series x/(1-x^{2}) +x^{2}/(1-x^{4}) +x^{4}/(1-x^{8}) +............ to infinite terms

**Asked By: TREEK**6 year ago

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2,4, 8, 16, 32, 64, ....,

**Asked By: NITESH CHANDU BHASARKAR**6 year ago

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what is the sum of all even integers between 99 and 301?

A)40000

B)20000

C)40400

D)20200

**Asked By: DINESH KHANNA**6 year ago

**Solved By: RSIVA**

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The sum of three positive real numbers x, y and z is 9. If the largest positive difference between any 2 of the 3 numbers is 5 and these 3 numbers are in arithmetic progression then the product of these 3 numbers will be what .please tell me.

**Asked By: S.NANDHINI**6 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

let the numbers are a-d, a, a+d

then according to the given condition a-d+a+a+d = 9 so 3a = 9 so a = 3

and [a+d]-[a-d] = 5 so 2d = 5 so d =5/2

now solve

The AM of two positive numbers a & b exceeds their GM by 3/2 & the GM exceeds the HM by 6/5 such that a+b= α , |a-b|=β , then which of them are correct,

1) α + β² = 96 2) α + β² =74 3)α²+β = 234 4)α²+β = 84

**Asked By: AMIT DAS**6 year ago

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**Answer Strategies and trick by Manish sir**(it will help you to solve it by yourself)

(a+b)/2 = √ab + 3/2 (1) or a+b = 2√ab + 3

√ab = 2ab/(a+b) + 6/5 (2) or 5(a+b)√ab = 10ab + 6(a+b)

on solving these 2 we get 5[2√ab + 3]√ab = 10ab + 6[2√ab + 3]

or 10ab + 15√ab = 10ab + 12√ab + 18

or 3√ab = 18 or ab = 36 and a+b = 15 = α

so a-b = √(225 - 144) = √81 = 9 = β