# 3 - Probability Questions Answers

There are 8 distinct boxes and each box can hold any number of balls. A child having 4 identical balls randomly choose four boxes. Then another child having four balls, identical to the previous mentioned, again puts one ball in each of the arbitrary chosen four boxes. The probability that there are balls in at least 6 boxes is

Sir pls solve

**Asked By: KANDUKURI ASHISH**

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**Asked By: LUFFY**

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**Joshi sir comment**

$Probabilitytogetfollowingdifferences\phantom{\rule{0ex}{0ex}}differenceprobability\phantom{\rule{0ex}{0ex}}06/36\phantom{\rule{0ex}{0ex}}110/36\phantom{\rule{0ex}{0ex}}28/36\phantom{\rule{0ex}{0ex}}36/36\phantom{\rule{0ex}{0ex}}44/36\phantom{\rule{0ex}{0ex}}52/36\phantom{\rule{0ex}{0ex}}Sorequiredprobability=1-2\left[\frac{6}{36}\left(\frac{4}{36}+\frac{2}{36}\right)+\frac{10}{36}\left(\frac{2}{36}\right)\right]\phantom{\rule{0ex}{0ex}}nowsolve\phantom{\rule{0ex}{0ex}}problemisbasedonintegralvaluessoareaisnotveryuseful$

**Asked By: SAHDEV SINGH**

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**Joshi sir comment**

1) (10/12)(9/11)(8/10)(7/9)

2) 4(10/12)(9/11)(8/10)(2/9)

3) (4*3/2)(10/12)(9/11)(2/10)(1/9)

4) 1 - (10/12)(9/11)(8/10)(7/9)