# 8 - Inverse Trigonometry Questions Answers

SinA 4/5 and cosB -12/13,find value of sin (A+B)
Asked By: PRIKSHIT 3 year ago

if [cot‾1 x]+[cos‾1 x] =0 then complete set of values of x is

Asked By: HARSHITA JAISWAL 4 year ago

value of ∑cot^-1(x^4+x^2+2/2x) is     (note summation vary from x=0to x=0∞)

Asked By: AMIT 4 year ago

If sin-1[2p / 1+p2 ] - cos-1[1-q2 / 1+q2]] = tan-1[2x / 1-x2] , prove that x = p-q / 1+pq ,where p,q belongs to (0,1)

Asked By: SHRISHTI 5 year ago

sin‾¹(sin2) + sin‾¹(sin4) + sin‾¹(sin6) = ?

Asked By: BONEY HAVELIWALA 5 year ago

sin‾¹(sin2) + sin‾¹(sin4) + sin‾¹(sin6)

= (π-2) + (π-4) + (6-2π)

= 0

If cos-1x - cos-1(y/2) = α , then 4x2-4xycosα + y2 is equal to ?

Asked By: AMIT DAS 6 year ago

according to the given condition

cos-1x  =  cos-1(y/2)  +  a

so x = cos ( cos-1y/2   +  a)

so x = y/2 cosa  -  sin cos-1y/2 + sina

so x = y/2 cosa  - [1-(y2/4)]1/2 + sina

so x - sina - y/2 cosa = -[1-(y2/4)]1/2

now square both side and solve

If  sin-1a + sin-1b+ sin-1c = π , then the value of { a√(1-a2) + b√(1-b2) + c√(1-c2)}

Asked By: AMIT DAS 6 year ago

let sin-1a = A ,    sin-1b = B    and    sin-1c= C

so  { a√(1-a2) + b√(1-b2) + c√(1-c2)}   = sinAcosA + sinBcosB + sinCcosC   = 1/2 (sin2A+sin2B+sin2C)

= 1/2 (4sinAsinBsinC)

= 2abc

If    [cot‾1x] + [cos‾1x] = 0 , then complete set of value of x is ( [ * ] is GIF)?

Asked By: AMIT DAS 6 year ago

These are the graphs for cot-1x and cos-1x

violet for cos and green for cot

from graph it is clear that cos part with integer function will be 0 for cos1<x≤1

and cot part with integer function will be 0 for cot1<x<∞