217 - Chemistry Questions Answers

no

AlF₃              5924 kJ/mol

Al₂O₃           15916 kJ/mol  

AlN               9506.8 kJ/mol

2KClO₃ ----------------------> 2KCl + 3O₂

3O₂ + 6H₂ --------------------> 6H₂O

6Zn + 6H₂SO₄ -------------------> 6ZnSO₄ + 6H₂

so 2 mole  KClO₃  -----------------------------  6 mole Zn

now solve

Integral enthalpy 

please check this word if wrong submit the correct question again

name is not correct

IUPAC name has four part

Extra Group................Main Chain............Bond Name..............Main Group

so name may be

*****..........................but........................an...................................2ol

****** means no extra group is present 

Main group is alcohol and its name is ol, 2 for second place in chain

"but" for 4 carbon and "an" for all single bond

so structure will be     CH₃CH(OH)CH₂CH₃

Energy = -13.6/n² ,  Potential Energy = -27.2/n²

for n = 3 we get -3.02  

in this answer infinite is zero potential energy level

NaNO₃  −−−−>    NaNO₂ + 1/2 O₂

molar mass of sodium nitrate = 85

so 85 gm will give 11200 ml O₂

so x gm will give 11200*x/85 = 2240x/17

on comparing with 44.8

we get 2240x/17 = 44.8

so x = 44.8*17/2240 = 17/50 = 34/100 = 0.34 gm

means 0.34 gm sodium nitrate is pure in 0.5 gm. sample so % purity = 0.34*100/0.50 = 68%

question is not complete, you should give the information about other elements present.

T α r/v    α is symbol for proportional

so f α v/r

v α 1/n

r α n²

now solve

O.N. change = 1-2 = -1

2 A are present so net change = 2

so e.w. = M/2