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Chemistry >> Physical Chemistry >> Chemical and Ionic Equilibrium Medical Exam

1-In the following hypothetical reaction A + 3B --------------

 2C + D, initial moles of A is twice that of B. If
at equilibrium moles of B and C are equal, % of B reacted is?
Asked By: SHWETA BHARDWAJ
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Joshi sir comment

     A + 3B ---------> 2C + D

     1    1/2                0     0

    1-x   1/2-3x          2x    x

according to the given condition 1/2 - 3x = 2x

                                        so 1/10 = x

so 3x = 3/10

so % = 0.3*100/0.5 = 60

Chemistry >> General Chemistry >> Mole Concept and Stoicheometry Others

Mole fraction of C2H5OH in aqueous solution is 0.25. If the density of solution is 0.967g/ml. calculate molarity and molality.

Asked By: NEHA RANI
is this question helpfull: 6 5 read solutions ( 2 ) | submit your answer
Joshi sir comment

0.75 mole water contains ...................................... 0.25 mole C2H5OH

so 0.75*18 gm contains ....................................... 0.25 mole

now calculate moles of alcohol in 1000 gm water. It will be molality

similarly

0.75 mole water contains ...................................... 0.25 mole C2H5OH

so 0.75*18 gm contains ....................................... 0.25*46 gm

so 0.75*18+0.25*46 gm solution contains ........................... 0.25 mole alcohol

so (0.75*18+0.25*46)*0.967 ml solution contains ............................. 0.25 mole alcohol

now calculate moles of alcohol in 1000 ml solution. It will be molarity

 

 

 

Chemistry >> Physical Chemistry >> Chemical Kinetics Engineering Exam
The following data was obtaind for the vapour phase decomposition of ethylene oxide into methane and carbon monoxide at 414.5'c. t,min p,mm hg 0 116.6 5 122.56 7 125.72 9 128.74 12 133.23 18 141.37 show that the reaction is first order and calculate the rate constant.
Asked By: BIBHUTI BHUSAN PADHI
is this question helpfull: 1 2 read solutions ( 3 ) | submit your answer
Joshi sir comment

                      C2H4O -------------->           CO           +           CH4

          t                                          P (C2H4O)

         0                                          116.6

         5                                          116.6-[122.56-116.6] = 116.6-5.96 = 110.64

         7                                           116.6-[125.72-116.6] = 116.6-9.12 = 107.48

   similarly others then find k for different readings by first order equation. k will be same for all readings.

       

Chemistry >> Inorganic Chemistry >> d and f block elements IIT JEE

what is the concept of finding different oxidation no. of f block elements.

Asked By: SHASHANK GUPTA
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Joshi sir comment

Different oxidation no. are shown by f group elements and it is the property of element so there is no definite rule for getting these ox. no. A general oxidation no. for a family can be understand but if element is showing more oxidation no. then you should remember it by remembering compounds in these oxidation no. 

Chemistry >> Inorganic Chemistry >> Co ordination compounds IIT JEE
When i am read dis chapter, a concept for classified monodentate ligand, biadentate ligand nd all of us r facing bt sir a can't learn how we classified. Plz give me a better suggestion?
Asked By: ARMAAN
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Joshi sir comment

The classification is based on the number of pairs of electrons a ligand can donate.

Chemistry >> General Chemistry >> Kinetic Theory of Gases IIT JEE

what is matter ???????????????

Asked By: M.ALI.MAMOON
is this question helpfull: 5 2 read solutions ( 1 ) | submit your answer
Joshi sir comment

matter is one of the fundamental constituent of the universe

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry IIT JEE

why heat of an ideal solution is taken as zero ?

Asked By: H. SHASHANK KUMAR
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Joshi sir comment

because in ideal solution there is no interaction between the two liquids present in the solution

Chemistry >> Physical Chemistry >> Thermodynamics and Thermochemistry IIT JEE

The enthalpy of nuutralisation of  a strong acid HA and weaker acid HB by KOH are -13.7 and -12.7 kcal/eq. When one equivalent of KOH is added to a mixture containing 1 eq of HA amd HB ; the enthaply change was -13.5 kcal. In what ratio is thge base distributeed between HA and HB ?

Asked By: H. SHASHANK KUMAR
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Joshi sir comment

let x in HA and 1-x in HB

so according to the given condition -13.7x-12.7(1-x) = -13.5

solve

Chemistry >> Physical Chemistry >> Solutions Board Exam
Why gas in gas not a solution
Asked By: JASEEM A RAHMAN P
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Joshi sir comment

gas in gas is a solution but interaction between the molecules play almost no role so these solutions are addressed as mixtures

Chemistry >> General Chemistry >> Atoms and molecules IIT JEE

A hydrogen like system has ionisation enthalpy 11808KJ/mol. find the no of protons in the nucleus of the system?

 

Asked By: MOHIT SAINI
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Joshi sir comment

A hydrogen like system has ionisation enthalpy 11808KJ/mol

on converting it into eV we get [11808*1000]/[6.023*1023*1.6*10-19]  = 122.53 eV

now formula for this energy is [-Z2/n2]13.6 eV

for n = 1, Z will be 3

 

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