166 - Questions Answers
y=px+a/p
this is a special type of differential equation in which p = dy/dx
its solution will be y = cx+(a/c) here c is a constant
y-xp=x+yp
on applying p = dy/dx
(ydx-xdy)/dx = (xdx+ydy)/dx
or ydx-xdy = xdx+ydy
or dy/dx = (y-x)/(y+x)
now it is homogeneous
1) Find the invariants of the matrix
0 1 0
0 0 0
0 0 0 of a linear transformation T in A(v) ?
2) Find the companion matrix of the polynomial ( x+1)2 ?
3) show that two real symmetric matrices are congruent if and only if they have the same rank and signature?
rank(A) = 1
det(A) = 0
trace(A) = 0
The matrix is not symmetric.
characteristic polynomial of the given matrix is x3
companion matrix of the polynomial (x+1)2
0 1
-1 -2
A real symmetric matrix of rank r is congruent over the field of real numbers to a canonical matrix
The integer p is called the index of the matrix and s = p - (r - p) is called the signature.
The index of a symmetric or Hermitian matrix is the number of positive elements when it is transformed to a diagonal matrix. The signature is the number of positive terms diminished by the number of negative terms and the total number of nonzero terms is the rank.
now solve it
A regular hexagon and a regular dodecagon are inscribed in the same circle. if the side of the dodecagon is (√3-1), then the side of hexagon is
for dodecagon sin(2π/40) = (a/2)/r so r = (a/2)/ sin(π/20)
now for hexagon sin(2π/12) = (x/2)/r so x/2 = r sin(π/6) = (a/2) sin(π/6)/ sin(π/20)
so x = (√3-1) (1/2) / ((√5-1)/4) here sin(π/20) = (√5-1)/4
or x = 4(√3-1) / 2(√5-1)
now solve it for further simplification
What are trigonometrical identities?
sin2A + cos2A = 1 and two similar formulae in terms of tanA, cotA, secA and cosecA
these are identities because these are true for all values of A
if secA-tanA=3
then find the value of (5cosA+4cotB)??
jus a hint
First replace cotB by cotA.
because it is wrongly printed by you.
answer by NIKHIL is correct
The sum of three positive real numbers x, y and z is 9. If the largest positive difference between any 2 of the 3 numbers is 5 and these 3 numbers are in arithmetic progression then the product of these 3 numbers will be what .please tell me.
let the numbers are a-d, a, a+d
then according to the given condition a-d+a+a+d = 9 so 3a = 9 so a = 3
and [a+d]-[a-d] = 5 so 2d = 5 so d =5/2
now solve
Importance High!!!!!!!!!!!!!!!!!
Dear Sir / Madam
Myself Rajeev Shrivastava, I am putting a signs series in front of you which based on numbers from 01 to 100. Actually I want to know that what reason of behind Approx equability of signs is
(++), (+-), (--) & (-+) at end of the month or year between the below mentioned.
Let's define a kind of mapping:
0↔1
2↔3
4↔5
6↔7
8↔9
(+) means: an Even number
(-) means: an Odd number
I simply say: for any EO (+-) it exists an OE (-+) which is paired to.
And that's true since each E is mapped to a O and vice versa (1 to 1 relation where "f(f(x))=x" ) !
E.g.: 29 ↔ 83
There is 25 numbers in the EO (+-) group, so 25 in OE (+-).
There is 25 numbers in the EE (++) group, so 25 in OO (--).
Picking a number at random between 01 and 100 inclusive is choosing equitably in EO, OE, EE or OO group. (25% for each)
So, I really need of your help to solve a puzzle please. I just am trying to make you understand what type of solution I need:
There are some results for your review:
MONTH |
DATE |
DAY |
FIRST_SERIES |
SECOND_SERIES |
FIRST_SERIES |
SECOND_SERIES |
||
APR |
1 |
SUN |
+ |
- |
- |
+ |
+- |
-+ |
APR |
2 |
MON |
+ |
+ |
- |
+ |
++ |
-+ |
APR |
3 |
TUE |
+ |
- |
+ |
- |
+- |
+- |
APR |
4 |
WED |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
5 |
THU |
- |
+ |
- |
+ |
-+ |
-+ |
APR |
6 |
FRI |
+ |
+ |
+ |
- |
++ |
+- |
APR |
7 |
SAT |
+ |
- |
- |
+ |
+- |
-+ |
APR |
8 |
SUN |
- |
+ |
+ |
- |
-+ |
+- |
APR |
9 |
MON |
- |
+ |
- |
+ |
-+ |
-+ |
APR |
10 |
TUE |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
11 |
WED |
+ |
+ |
- |
- |
++ |
-- |
APR |
12 |
THU |
- |
+ |
- |
- |
-+ |
-- |
APR |
13 |
FRI |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
14 |
SAT |
+ |
- |
+ |
- |
+- |
+- |
APR |
15 |
SUN |
+ |
- |
+ |
- |
+- |
+- |
APR |
16 |
MON |
- |
- |
+ |
+ |
-- |
++ |
APR |
17 |
TUE |
- |
- |
+ |
+ |
-- |
++ |
APR |
18 |
WED |
|
|
|
|
|
|
APR |
19 |
THU |
|
|
|
|
|
|
APR |
20 |
FRI |
|
|
|
|
|
|
APR |
21 |
SAT |
|
|
|
|
|
|
APR |
22 |
|
|
|
|
|
|
|
APR |
23 |
|
|
|
|
|
|
|
(Complete sheets for the year 2011 and 2012 are attached with this mail)
You can see that there are two times falls in a day of pair make by even (+) and odd (-) signs, i.e. (++), (+-), (--) & (-+) as above said.
The total of pair combination signs become approx equal to each other at the end of the month or year (every year- so, I am sending you attachment to go through the year’s result).
By this analysis:
1- I want to know that what is the relation between current falling signs and past fell signs.
2- How can I come to know, what type of combination of sign would be any particular date or day.
3- As you can seen on 22nd and 23rd April’2012 I don’t know what combination of sign is.
4- There is surety that there is some relation between current First fall of combination of signs and past fall or First fall of combination of signs and Second fall of combination of signs.
Please help me to how come to know what type of fall may be for next day by reviewing past or first combination of signs. So reply or elaborate me with an example.
I would be very grateful to you till entire life.
Regards
RAJEEV SHRIVASTAVA
Importance High!!!!!!!!!!!!!!!!!
Dear Sir / Madam
Myself Rajeev Shrivastava, I am putting a signs series in front of you which based on numbers from 01 to 100. Actually I want to know that what reason of behind Approx equability of signs is
(++), (+-), (--) & (-+) at end of the month or year between the below mentioned.
Let's define a kind of mapping:
0↔1
2↔3
4↔5
6↔7
8↔9
(+) means: an Even number
(-) means: an Odd number
I simply say: for any EO (+-) it exists an OE (-+) which is paired to.
And that's true since each E is mapped to a O and vice versa (1 to 1 relation where "f(f(x))=x" ) !
E.g.: 29 ↔ 83
There is 25 numbers in the EO (+-) group, so 25 in OE (+-).
There is 25 numbers in the EE (++) group, so 25 in OO (--).
Picking a number at random between 01 and 100 inclusive is choosing equitably in EO, OE, EE or OO group. (25% for each)
So, I really need of your help to solve a puzzle please. I just am trying to make you understand what type of solution I need:
There are some results for your review:
MONTH |
DATE |
DAY |
FIRST_SERIES |
SECOND_SERIES |
FIRST_SERIES |
SECOND_SERIES |
||
APR |
1 |
SUN |
+ |
- |
- |
+ |
+- |
-+ |
APR |
2 |
MON |
+ |
+ |
- |
+ |
++ |
-+ |
APR |
3 |
TUE |
+ |
- |
+ |
- |
+- |
+- |
APR |
4 |
WED |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
5 |
THU |
- |
+ |
- |
+ |
-+ |
-+ |
APR |
6 |
FRI |
+ |
+ |
+ |
- |
++ |
+- |
APR |
7 |
SAT |
+ |
- |
- |
+ |
+- |
-+ |
APR |
8 |
SUN |
- |
+ |
+ |
- |
-+ |
+- |
APR |
9 |
MON |
- |
+ |
- |
+ |
-+ |
-+ |
APR |
10 |
TUE |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
11 |
WED |
+ |
+ |
- |
- |
++ |
-- |
APR |
12 |
THU |
- |
+ |
- |
- |
-+ |
-- |
APR |
13 |
FRI |
+ |
+ |
+ |
+ |
++ |
++ |
APR |
14 |
SAT |
+ |
- |
+ |
- |
+- |
+- |
APR |
15 |
SUN |
+ |
- |
+ |
- |
+- |
+- |
APR |
16 |
MON |
- |
- |
+ |
+ |
-- |
++ |
APR |
17 |
TUE |
- |
- |
+ |
+ |
-- |
++ |
APR |
18 |
WED |
|
|
|
|
|
|
APR |
19 |
THU |
|
|
|
|
|
|
APR |
20 |
FRI |
|
|
|
|
|
|
APR |
21 |
SAT |
|
|
|
|
|
|
APR |
22 |
|
|
|
|
|
|
|
APR |
23 |
|
|
|
|
|
|
|
(Complete sheets for the year 2011 and 2012 are attached with this mail)
You can see that there are two times falls in a day of pair make by even (+) and odd (-) signs, i.e. (++), (+-), (--) & (-+) as above said.
The total of pair combination signs become approx equal to each other at the end of the month or year (every year- so, I am sending you attachment to go through the year’s result).
By this analysis:
1- I want to know that what is the relation between current falling signs and past fell signs.
2- How can I come to know, what type of combination of sign would be any particular date or day.
3- As you can seen on 22nd and 23rd April’2012 I don’t know what combination of sign is.
4- There is surety that there is some relation between current First fall of combination of signs and past fall or First fall of combination of signs and Second fall of combination of signs.
Please help me to how come to know what type of fall may be for next day by reviewing past or first combination of signs. So reply or elaborate me with an example.
I would be very grateful to you till entire life.
Regards
RAJEEV SHRIVASTAVA
If you are making the sequence on the basis of dates then you should take signs accordingly then you can make this sequence for many years
for example if you take 23 june then first sign series will be +-, + for even number and - for odd number , now as conversion rule as you gave in your explanation 23 will be converted to 32 so second series will be -+
similarly you can make it for any date
for example 29 december first series will be +- and its conversion is 38 so next series will be -+
if you are thinking something else then explain your question correctly
how to find differential eqn. of all conics whose axes coincide with coordinate axes?? tell me the eqn. of tht. conic
Parabola eq. y2 = 4ax ,
on differentiating this eq. with respect to x we get 2y(dy/dx) = 4a
on taking this value of 4a in eq. y2= 4ax we will get the differential eq. of parabola.
similarly for ellipse x2/a2 + y2/b2 = 1
on differentiaing this eq. twice we will get two additional eq.
by solving these eq. get an eq. free from a and b, this will be the differential eq. of the ellipse.
similarly for hyperbola
Which of the following angles are co-terminal angles: 480 , -240 or 600
how can we get it which is co-terminal and what does co-terminal means?????
Coterminal angles are angles in standard position (angles with the initial side on the positive x-axis) that have a common terminal side. For example 30°, –330° and 390° are all coterminal.
To find a positive and a negative angle coterminal with a given angle, you can add and subtract 360° if the angle is measured in degrees or 2π if the angle is measured in radians.
480 and -240 are co terminal angles because 480-360 = 120 and -240+360 = 120