18 - Capacitors Questions Answers
initial energy of capacitor = 1/2 CV2
final energy of capacitor = 1/2 KC (V/K)2
difference ?
initial energy of capacitor = 1/2 CV2
final energy of capacitor = 1/2 KC (V/K)2
difference ?
Calculate potential difference across a and b ,
since net potential = 0, answer will be 0 for the given diagram. By interchanging the poles of any one battery this question will become meannigfull so change it and apply Kirchhoff law.
a 24.6 mev alpha particle moves towards gold nucleus[atomic no 79] calculate the distance of closest approach of alpha particle
upto closest approach total KE of α particle will become PE
so use the formula KE = 9*109 * Ze2e/r
here KE = 24.6 mev convert it into joule first
solve equation for r
V = Ed = 6* 107*0.002
Define Potential Energy?
Potential energy is the energy of a particle due to its position relative to the reference point taken.
Q Q1=1.5C , R1=2M, Q2 =3C&R2=1M WHEN THESE SPHERICAL CAPACITER TOUCHED EACH OTHER THEN CHARGE WILL MOVE OR NOT . IF MOVE THEN HOW MUCH
(MANIPAL 2012)
on touching, the new ratio of charges = x/y = 2/1 this is by the formula q1/q2 = C1/C2 = R1/R2
and x+y = 1.5+3 = 4.5
or 2y+y = 4.5
or y = 1.5
so 1.5 C will move from second to first.
what is the main use of capacitors
Capacitor :- A capacitor is a device to store energy