47 - Rotational mechanics Questions Answers

Asked By: TUSHAR GUPTA
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Asked By: TUSHAR GUPTA
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Joshi sir comment
Please upload solution. Thanks in advance. 
Asked By: TUSHAR GUPTA
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Joshi sir comment
Please post its solution sir, thanks in advance. 
Asked By: TUSHAR GUPTA
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Sir please take this question as a Youtube video. Your explanation is great.
Asked By: AMAN KUMAR
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Joshi sir comment

No horizontal force.

Draw a perpendicular from centre to horizontal plane. Then calculate horizontal distance. 

Now solve. 

If any problem, then inform

How to solve this?
Asked By: AVRANIL SAHA
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Joshi sir comment

In first case F = 2T = 150 so T = 75 newton,  Now in second case system is free to move acceleration of the system a = F/20 for 10 kg rod F-2T = 10a = 10(F/20) = F/2 F-(F/2)=2T F=4T = 300 newton 

what is the moment of inertia of a cube about its diagonal?

Asked By: SHIV GOVIND
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Joshi sir comment

Moment of inertia of a cube about a line perpendicular to its one face and passing through its centre is ma2/6 so about diagonal inertia = l2Ix+m2Iy+n2Iz  = (l2+m2+n2)Ix    (here Ix=Iy=Iz) = Ix  = ma2/6 l,m,n are direction cosines of three lines passing througe centre of cube and perpendicular to each other

Pls give Solution
Asked By: PRIYANSHU SINGH
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Joshi sir comment

A rotating ball hits a rough horizontal plane with a vertical velocity v and angular velocity w. Given that the coefficient of friction is u and the vertical component of the velocity after the collision is v/2, find:

a) the angular velocity after collision;

b) the impulsive ground reaction during the collision

Asked By: UDDESH KUMAR SABAT
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Joshi sir comment

on applying momentum impulse theorem along vertical

-mv+Ndt = mv/2       (1)

by angular momentum angular impulse theorem

2mωr2/5 - μNdtr = 2mω,r2/5       (2)By eq. (2) get angular velocity.

impulsive ground reaction = (Ndt)2+(μNdt)2by using eq. (1), solve it

What is the minimum coefficient of friction for a solid sphere to roll without slipping on an inclined plane of inclination θ?

Asked By: SWATI KAPOOR
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Joshi sir comment

friction f = mgsinθ/[1+(mr2/I)]

solve for sphere and compare to μmgcosθ

 

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