40 - Electric Field and Potential Questions Answers

Answer in lower image .Dear Sir,Kindly help solve.
Asked By: RK GUPTA
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Asked By: ABHISHEK
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All options are dimensionally incorrect. Please rectify.

 

Derive the expression or show that:Path independence of line integral of electrostatic field,, conservative nature of electrostatic force.

Asked By: SANJAY
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See the clip

Asked By: TUSHAR GUPTA
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Find potential energy of disc having charge density sigma uniformly distributed on its surface,radius R

Asked By: AKASH MAURYA
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Let potential of a disc of radius x is V. For this, see video given below

Now potential energy of this disc with a circular layer of charge2πxdxσ is V2πxdxσ put the value of V and integrate inform for any problem 

 

Asked By: SRIJAN
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We know that planeEdScosθ = q6ε0   (1) and Net force on the plane =planeFdQ  =plane qEcosθdSσ =Qd2plane qEcosθdS   (2) Now solve eq. (1)and (2)

A hollow spherical shell of radius r has a uniform charge density sigma. It is kept in a cube of edge 3r such that the center of the cube coincides with the centre of the shell. The electric flux coming out of a face of the cube is

 

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Asked By: KANDUKURI ASHISH
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Total flux in 6 faces =σ4πr2ε0   so in 1 face = 16σ4πr2ε0  if any issue, inform

A solid conducting sphere of radius R is placed in a uniform electric field E as shown in figure-1.441. Due to electric field non uniform surface charges are induced on the surface of the sphere. Consider a point A on the surface of sphere at a polar angle θ from the direction of electric field as shown in figure. Find the surface density of induced charges at point A in terms of electric field and polar angle θ.

 

 

Asked By: DEBRAJ SAHA
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To nullify the electric field inside, the conducting sphere creates a situation in which electric field inside due to charge on sphere would be same as that of given electric field. Now this is the case, which is same as Irodov 3.17.

See the video now

link:

FinallyE = σ03ε0 = σ3ε0cosθ Now solve

a small ball of mass 1kg and a charge 2/3 uC is placed at the center of a uniformly charged sphere of radius 1m and charge 1/3 mC. a narrow smooth horizontal groove is made in the sphere from centre to surface as shown in figure. the sphere is made to rotate about its vertical diameter at a constant rate of 1/2pi revolutions per second. find the spedd w.r.t ground with which the ball slide out from the groove. neglect any magnetic force acting on ball?

Asked By: VISHNU VARDHAN
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Potential difference from centre to surface = 3V/2 - V = V/2 here V = kq/r (q is charge of sphere) mvr2/2 = VQ/2 (Q is charge of particle) vr is radial velocity Besides tangential velocity due to rotation of sphere = rω=r2πn now solve  

Asked By: BHASKAR JHA
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By volume comparision radius of combined drop = 21/3r net charge in the new drop = 2q now put these values in the formula of potential 

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