16 - Heat Transfer Questions Answers

The moment of inertia of the body about an axis is 1.2 kg-m2. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500 J, an angular acceleration of 25 rad/s2 must be applied about the axis for the duration of

Asked By: SAUMYA PALIWAL 5 year ago

The Poisson’s ratio of a material is 0.5. if a force is applied to a wire of this material, there is a decrease in the cross-sectional area by 4%. The percentage increase in the length is

Asked By: SAUMYA PALIWAL 5 year ago

The temperature of a perfect black body

is 1000k and its area

is 0.1m2 . the heat radiated by it in 1 minute in joule is

Asked By: HASITHA.KOTTA 6 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

Q/At = σT4

now solve

a thin square plate with each side equal to 10cm , is heated by a blacksmith . the rate radiated energy by the heated plate is 1134W the temp of hot square plate is

( σ = 5.67 X 10-8 Wm2/k4 emissivity of plate =1)

ANS 1000K

Asked By: SARIKA SHARMA 7 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

according to the Stefans law P = AeσT4

so 1134 = 0.02*1*5.67*10-8*T4   (area of both the faces are considered)

so 1134*1010/11.34 = T4

so T = 1000

the density of two substances are in ratio 5:6 & specific heat are in ratio 3:5. their thermal capacity per unit volume will be in ratio?

ans 1:2

Asked By: SARIKA SHARMA 7 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

thermal capacity = ms = Vds

so thermal capacity per unit volume = ds

it takes 6 hours for ice layer thickness to grow from 1cm to 2cm on a lake in Siberia, ideally the time taken for thickness to grow from 3cm to 4cm?

ans 14 hrs

Asked By: SARIKA SHARMA 7 year ago
is this question helpfull: 4 4 read solutions ( 1 ) | submit your answer
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

for this type of question relation between time and thickness will be

[x2] α t

so 22 - 12 = k6

and 42 - 3= kt

on dividing we will get 3/7 = 6/t

or t = 14

Q  HEAT & WORK ARE EQUIVALENT. THIS MEANS

TEMP OF BODY CAN BE INCREASED BY DOING WORK ON IT. PLS TELL HOW THIS STAT. IS CORRECT.Q

Q IF H IS SUPPLIED TO IDEAL GAS IN ISO PROCESS. THEN W= +ve HOW? BECAUSE IF ISO THEN U= 0 & EQN IS Q=W+0 & H IS SUPPLIED SO Q=-veSO W =-ve.so ans shd be -veBUT ANS GIVEN IS +ve PLS TELL ANS WITH EXPL. THANKS FOR PRE SOLUTIONS .

Asked By: SARIKA 7 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

This means heat can be used to make work and work done produces heat

By doing 4.2 joule work 1 cal. heat will be produced in a body so due to this 1 cal, temp. will increase

In physics heat is supplied means Q will be +ve so W will also be positive hence is correct. A system is placed in refrigrator for absorbing heat from the body, this process will have Q -ve.

a hollow sphere of mass M (in K.G.) radius R (in m.)  is rotating with angular  frequency  omega(in radsec)  . it suddenly stops rotating and 75% of  the K.E. converted  into heat energy .   if S joulekg-kelvin is the spesific heat of material of the sphere, the rise of temperature of the sphere is ?

Asked By: SHUBHAM VED 7 year ago
is this question helpfull: 5 6 read solutions ( 1 ) | submit your answer
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

Rotational K. E. = 1/2 I ω2

so 0.75 [1/2 I ω2] = M S dT

and I = 2/3 M R2

now solve

two identical conducting rods are first connected independently to  two vessels, one containing water at 100°C and the other containing ice at 0°C. In the second case, the rods are joined end to end connected to the same vessels. Let M1 and M2 g/s be the rate of melting of ice in the two cases respectively, the ratio M1/M2 is

(1) 1:2

(2) 2:1

(3) 4:1

(4) 1:4

Asked By: HIMANSHU MITTAL 7 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

in first case rods are taken in parellel so net length and area will be l and 2A with conductivity coefficient K

similarly in second case rods are taken in series so net length and area will be 2l and A with conductivity coefficient K

now use H = KA(θ1- θ2)/L and  H = dQ/dt = mL/t     L is latent heat which is fixed in both the cases

Three discs A,B and C having radii 2m, 4m and 6m respectively are coated with carbon black on their outer surfaces. the wavelenghts corresponding to maximum intensity are 300 nm, 400nm and 500 nm respectively. if the power radiated by them are Qa, Qb and Qc respectively then

(1) Qa is maximum

(2) Qb is maximum

(3) Qc is maximum

(4) Qa= Qb = Qc

Asked By: HIMANSHU MITTAL 7 year ago
Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

according to Wein's displacement law λT = constant

so ratio of temperatures of the three discs will be 1/3:1/4:1/5 = 20:15:12

and ratio of area of the discs = 1:4:9

now according to Stephan's law Q α  A * T4

so ratio Qa:Qb:Qc = 1*(20)4 : 4*(15)4 : 9*(12)4

on solving we will get that Qis maximum