14 - Moving charge magnetism and force in magnetic field Questions Answers

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

An electron originates at a point A lying on the axis of a straight solenoid and moves with a velocity v at an angle α to the axis. The magnetic induction of the field is B. Find the distance r from the axis to the point on the screen into which the electron strikes. The screen is oriented at right angles to the axis and is located at a distance l from the point A.

Thanks in advance sir.

Asked By: PRABHAN BUGATHA

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Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Please post solution sir, thanks in advance.

Asked By: TUSHAR GUPTA

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Joshi sir comment

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Olympiad

Asked By: TUSHAR GUPTA

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Joshi sir comment

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Olympiad

Asked By: TUSHAR GUPTA

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Joshi sir comment

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: TUSHAR GUPTA

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Joshi sir comment

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: KESHAV

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Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: LUFFY

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Joshi sir comment

$M a g n e t i c t o r q u e = \vec{M} \times \vec{B} = i \vec{A} \times \vec{B} T o r q u e d u e t o g r a v i t y a b o u t t h e p o i n t o f c i r c u m f e r e n c e = \vec{R} \times m \vec{g} N o w c o m p a r e t h e t w o$ Inform for any issue

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Board Exam

CALCULATE THE MAGNETIC FIELD AT THE CENTRE OF SQUARE WIRE OF SIDE (2)^1/2cm AND CARRYING A CURRENT OF 10A.?

Asked By: GAUTAM SAGAR

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Joshi sir comment

method given by BONEY is correct but formula is not correct

it should be B = 4×{ (μ₀I) / 4πR } × [sinθ₁+ Sinθ₂]

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Medical Exam

two short magnets of equal dipole momet M are fastened perpedicularat their centre.the magnitude of magnetic feild at adistance d from the centre on the bisector of right angles is?

Asked By: AKANKSHA Solved By: SARIKA

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Joshi sir comment

the resultant dipole moment is √2M thus the resultant magnetic field is μ2√2M/4πd³ (ans)

this answer is given by sarika and is correct answer

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Medical Exam

Physics >> Magnetism >> Moving charge magnetism and force in magnetic fieldMedical Exam

velocity of e^- in hydrogen atom is 2X10⁶ m/s . the radius of orbit is 5X10^-11 m . the mag induction at centre of orbit in T will be??

Asked By: SARIKA 1 Month ago

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Asked By: SARIKA SHARMA

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Joshi sir comment

B = μ₀/2 * i/r

and i = e/T

and T = 2πr/v

solve

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