# 13 - Moving charge magnetism and force in magnetic field Questions Answers

Joshi sir comment
Joshi sir comment
Joshi sir comment
Joshi sir comment

Inform for any issue

CALCULATE  THE MAGNETIC FIELD  AT THE CENTRE OF SQUARE WIRE OF SIDE (2)1/2cm  AND CARRYING A CURRENT OF 10A.?

Joshi sir comment

method given by BONEY is correct but formula is not correct

it should be B = 4×{ (μ0I) / 4πR } × [sinθ1+ Sinθ2]

two short magnets of equal dipole momet M are fastened perpedicularat their centre.the magnitude of  magnetic feild at adistance d from the centre on the bisector of right angles is?

Asked By: AKANKSHA Solved By: SARIKA
Joshi sir comment

the resultant dipole moment is √2M  thus  the resultant magnetic  field is  μ2√2M/4πd3   (ans)

velocity of e- in hydrogen atom is 2X106 m/s . the radius of orbit is 5X10-11 m . the mag induction at centre of orbit in T will be??

Asked By: SARIKA 1 Month ago

Joshi sir comment

B = μ0/2 * i/r

and i = e/T

and T = 2πr/v

solve

potential diff b/w dees of cyclotron is V , if charge q comes out of it after completing n revolution then gain in KE of charge is 2nqV HOW?

Asked By: SARIKA 1 Month ago