4 - Simple Harmonic Motion Questions Answers

Asked By: TUSHAR GUPTA
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small ring is threaded on an inextensible frictionless cord of length 2l.

The ends of the cord are fixed to a horizontal ceiling. In equilibrium, the  

ring is at a depth h below the ceiling. Now the ring is pulled aside by a  

small distance in the vertical plane containing the cord and released.  

Find period of small oscillations of the ring. Acceleration of free fall is g.

Asked By: ABHISHEK KHANDELWAL
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Joshi sir comment

 

TWO PENDULUM HAVE TIME PERIODS T &5T/4. THEY STARTS SHM AT THE SAME TIME FROM THE MEAN POSITION . WHAT WILL BE THE PHASE DIFFERENCE B/W THEM AFTER D BIGGER PENDULUM COMPLETED ONE OSCILLATn ??

ans 900

Asked By: SARIKA SHARMA
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Joshi sir comment

When bigger pendulum will complete its one oscillation, the smaller one will complete [1+(1/4)] oscillation. so phase difference = 2π*(T/4)/T = π/2

2 comparable masses m1 and m2  r orbiting about their bodycenter o at distance r1 and r2 from  their  body center respectively  with a common period T. the squar of time period  ?

Asked By: SHUBHAM VED
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Joshi sir comment

 

According to the diagram 

Gm1m2/(r1+r2)2 = m1r1ω2 = m2r2ω2

compare first part with either second or third part of the given equation for getting ω2 then find T2

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