102 - Kinematics Questions Answers

Physics >> Mechanics part 1 >> Kinematics IIT JEE

At t = 0, a stone is dropped into a well in which the level of water is h below the top of the well. If v is velocity of sound, the time T measured from t = 0, after which the splash is heard is given by ?

Asked By: PREM

is this question helpfull: 0 0 submit your answer

Joshi sir comment

$B y h = u t + \frac{1}{2} a t^{2}, t i m e o f d o w n w a r d j o u r n e y c a n b e c a l c u l a t e d t h e n h / v i s t h e t i m e f o r u p w a r d j o u r n e y o f s o u n d n o w s o l v e$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Sir can you please solve this question??? Thank you very much sir

Asked By: GOLU

is this question helpfull: 3 0 submit your answer

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Asked By: SYED SAHIB AKTAR

is this question helpfull: 1 0 submit your answer

Joshi sir comment

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Sir pls solve

Asked By: KANDUKURI ASHISH

is this question helpfull: 1 0 submit your answer

Joshi sir comment

$I m p u l s e i s \vec{F t} a n d P o w e r = W / t \vec{F} = m \vec{g} a n d W = m g h N o w c a l c u l a t e t h e t i m e o f m o t i o n a n d g e t t h e a n s w e r$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Sir please make a video explaining this problem solution as i love your explanation

Asked By: PRATEEK MOURYA

is this question helpfull: 0 0 submit your answer

Joshi sir comment

$A c c o r d i n g t o g i v e n c o n d i t i o n \frac{d θ}{d t} = \frac{v \sin 60}{a - (v + v \cos 60) t} N o w s o l v e i t f o r t t h e n d i s \tan c e = v t$ solve

inform for any difficulty

Physics >> Mechanics part 1 >> Kinematics IIT JEE

A long smooth cylindrical pipe of radius r is tilted at an angle alpha to the horizontal. A small body at point A is pushed upwards along the inner surface of the pipe so that the direction of its initial velocity forms an angle phi with generatrix AB. Determine the minimum initial velocity V at which the body starts moving upwards without being separated from the surface of the pipe

Asked By: MAAZ

is this question helpfull: 3 0 submit your answer

Joshi sir comment

At the front of the cylinder, see a tilted circle $N o w c o m p a r e t h i s p r o b l e m w i t h v e r t i c a l c i r c u l a r m o t i o n . A i s t h e t o p p o i n t o f t h a t p a t h . W e k n o w t h a t t h e m i n i m u m v e l o c i t y a t t o p p o i n t \tan g e n t i a l t o p a t h o f v e r t i c a l c i r c l e s h o u l d b e \sqrt{g r} . H e r e d u e t o t i l t o f t h i s c i r c l e e f f e c t i v e g r a v i t y = g \cos α s o v \sin φ = \sqrt{g \cos α r} n o w s o l v e i n f o r m f o r a n y i s s u e w a i t f o r v i d e o$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Asked By: KANDUKURI ASHISH

is this question helpfull: 0 0 submit your answer

Joshi sir comment

According to first given condition velocity component of rain = u

let vertical component of rain = v

According to second condition

velocity of rain relative to man

$= (n u - u) (- \hat{i}) + v (- \hat{j})$ $h e r e d i r e c t i o n o f m o t i o n o f m a n i s \hat{i} a n d v e r t i c a l l y u p w a r d d i r e c t i o n i s c o n s i d e r e d a s \hat{j} N o w d r a w t r i a n g l e f o r t h i s v e c t o r a n d g e t c o t θ s o l v e i t i n f o r m f o r a n y i s s u e$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

A cylindrical pipe of radius r is rolling towards a frog sitting on the horizontal ground. Center of the pipe is moving with velocity v. To save itself ,the frog jumps off and passes over the pipe touching it only at top. Denoting air time of frog by T, horizontal range of the jump by R and acceleration due to gravity by g. Find T and R.

Asked By: MUDIT

is this question helpfull: 3 0 submit your answer

Joshi sir comment

$A c c o r d i n g t o g i v e n c o n d i t i o n 2 r = {u_{y}}^{2} / 2 g, T = 2 u_{y} / g = 2 \sqrt{4 g r} / g = 4 \sqrt{r / g} A t t o p p o i n t d u e t o t o u c h, v e c o c i t y o f t h e f r o g b e u_{x} - 2 v . R = [u_{x} u_{y} / g] + [u_{x} - 2 v) u_{y} / g] = [u_{y} / g] (2 u_{x} - 2 v) = [2 u_{y} / g] (u_{x} - v) = T (u_{x} - v) N o w m i n i m u m p o s s i b l e v a l u e o f v e l o c i t y o f f r o g a t t o p t o c r o s s t h e c y l i n d e r i s \sqrt{g r} (B y t h e c o n c e p t o f v e r t i c a l c i r c l e) n o w s o l v e c a r e f u l l y w i t h o u t e r r o r$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

A small ball is thrown from foot of a wall with minimum possible velocity to hit a bulb B on the ground at a distance L away from the wall.Find the expression for height h of shadow of the ball on the wall as a function of time t.Acceleration due to gravity is g.

Asked By: MUDIT

is this question helpfull: 1 0 read solutions ( 1 ) | submit your answer

Joshi sir comment

Physics >> Mechanics part 1 >> Kinematics IIT JEE

While making this paper, I stayed up till late at night working with candle light. I had two

candles of equal length L lit and placed at the same time, as shown in the figure. Immediately

thereafter I noticed that the shadow of the first candle on the left wall is not changing in

length, and the shadow of the second candle on the right wall is being shortened at a speed v.

(Take d1

= 10 cm, d2

= 20 cm, d3

= 30 cm, v = 1 mm/s, L = 20 cm.)

Asked By: AAYUSH MALAVIYA

is this question helpfull: 0 1 submit your answer

Joshi sir comment

Problem is interesting yet not complete. Complete it to get answer

thanks

Login Here

Username / Email :

Registration Form

Your Full Name :

Your Email Address :

Password :

Country :

State :

102 - Kinematics Questions Answers

Login Here

Forget Password

Registration Form