102 - Kinematics Questions Answers

 At t = 0, a stone is dropped into a well in which the level of water is h below the top of the well. If v is velocity of sound, the time T measured from t = 0, after which the splash is heard is given by ?

 

Asked By: PREM
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Joshi sir comment

By h=ut+12at2, time of downward journey can be calculated then h/v is the time for upward journey of sound now solve

Sir can you please solve this question???  Thank you very much sir 
Asked By: GOLU
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Asked By: SYED SAHIB AKTAR
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Joshi sir comment

Sir pls solve

Asked By: KANDUKURI ASHISH
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Joshi sir comment

Impulse is Ft and Power = W/t F=mg and W = mgh Now calculate the time of motion  and get the answer

Sir please make a video explaining this problem solution as i love your explanation
Asked By: PRATEEK MOURYA
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Joshi sir comment

According to given condition dθdt=vsin60a-(v+vcos60)t Now solve it for t then distance = vtsolve 

inform for any difficulty

A long smooth cylindrical pipe of radius r is tilted at an angle alpha to the horizontal. A small body at point A is pushed upwards along the inner surface of the pipe so that the direction of its initial velocity forms an angle phi with generatrix AB. Determine the minimum initial velocity V at which the body starts moving upwards without being separated from the surface of the pipe

Asked By: MAAZ
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Joshi sir comment

At the front of the cylinder, see a tilted circle Now compare this problem with vertical circular motion. A is the top point of that path. We know that the  minimum velocity at top point tangential to path of  vertical circle should be gr. Here due to tilt of this circle effective gravity = gcosα so vsinφ =gcosαr now solve inform for any issue wait for video

Sir please give hint 
Asked By: KANDUKURI ASHISH
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Joshi sir comment

According to first given condition velocity component of rain = u

let vertical component of rain = v

According to second condition 

velocity of rain relative to man 

=(nu-u)(-i^)+v(-j^)here direction of motion of man is i^ and  vertically upward direction is considered as j^ Now draw triangle for this vector and get cotθ solve it  inform for any issue 

A cylindrical pipe of radius r is rolling towards a frog sitting on the horizontal ground. Center of the pipe is moving with velocity v. To save itself ,the frog jumps off and passes over the pipe touching it only at top. Denoting air time of frog by T, horizontal range of the jump by R and acceleration due to gravity by g. Find T and R.

Asked By: MUDIT
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Joshi sir comment

According to given condition 2r = uy2/2g, T= 2uy/g =24gr/g=4r/g At top point due to touch, vecocity of the frog be ux2v. R=[uxuy/g]+[ux2v)uy/g]=[uy/g](2ux2v) =[2uy/g](uxv) =T(uxv) Now minimum possible value of velocity of frog at top to  cross the cylinder is gr (By the concept of vertical circle) now solve carefully without error

A small ball is thrown from foot of a wall with minimum possible velocity to hit a bulb B on the ground at a distance L away from the wall.Find the expression for height h of shadow of the ball on the wall as a function of time t.Acceleration due to gravity is g.

Asked By: MUDIT
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Joshi sir comment

While making this paper, I stayed up till late at night working with candle light. I had two

candles of equal length L lit and placed at the same time, as shown in the figure. Immediately

thereafter I noticed that the shadow of the first candle on the left wall is not changing in

length, and the shadow of the second candle on the right wall is being shortened at a speed v.

(Take d1

= 10 cm, d2

= 20 cm, d3

= 30 cm, v = 1 mm/s, L = 20 cm.)

Asked By: AAYUSH MALAVIYA
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Joshi sir comment

Problem is interesting yet not complete. Complete it to get answer 

thanks

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