7 - Fluid in motion Questions Answers

Sir tell how to write time period eq for this question
Asked By: ANVESH
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Sir please solve i am not able to get
Asked By: KANDUKURI ASHISH
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Joshi sir comment

By Bernoullis theorem, velocity of water jet = 2ghWater jet comes out perpendicular to surface.

 make its horizontal and vertical components

By vertical component, calculate time, then use it with 

horizontal velocity component to get distance along x axis

Finally calculate distance from centre, along x axis 

 

Inform for any confusion

Plzz solve all the intigrations step by step ☺️☺️☺️.plzz
Asked By: ASHLOK
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Joshi sir comment

can the linear speed of two objects be different if they have the same angular speed?

Asked By: VIBHU GOEL
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Joshi sir comment

angular speed depends on the distance from pivot also so v may be same or different 

formula affilated is v = r ω

THE  TERMINAL SPEED ATTAINED BY AN Al  SPERE OF RADIUS 1mm  FALLING THROUGH H2O AT 200C WILL BE CLOSE TO ??

ANS 4.6 m/s

(assume laminar flow , specific gravity of Al=2.7 & η H2O =8X 10-4 PL.)

Asked By: SARIKA SHARMA
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Joshi sir comment

v = 2r2g(D-d)/9η

so v = 2(.001)2*9.8(2700-1000)/9*8*10-5

solve it 

Q IF IN THE SAME QUESTn OF BAROMETER THE ELEVATOR IS ACCELERATING UPWARD READS 76cm. THEN AIR PRESSURE IN ELEVATOR IS >76cm PLS EXPLAIN THE CONCEPT BEHIND SUCH CASES.

Asked By: SARIKA
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Joshi sir comment

when elevator will move in upward direction the extra Hg level will feel a down force and given that in movable condition it is 76 cm. Hg so really it will be more than 76 cm. 

There is some amount of water in the beaker, and a vertical  rod is passing through the centre of the circular base of the cylindrical beaker which is rotated with angular velocity ω  , then water takes a particular shape(miniscus is formed). Find the equation of the miniscus of water when the mid point of  the miniscus just touches the bottom surface of the beaker?

Asked By: AMIT DAS
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Joshi sir comment

after making the diagram, complete the miniscus as a sphere, then following conditions will be obtained

1) h = R(1-cosθ)  here h, R and θ are height of miniscus, radius of the sphere and  contact angle.

2) R = r/cosθ, r is the radius of beaker

3) tanθ = g/rw2

4) πr2hρ - πR3ρcos2θ = 2πrTcosθ

There are 4 equations, remove R, θ and T and get a relation between h and r in terms of g, w, ρ and π

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