8 - Fluid in motion Questions Answers

A man travels one third part of his total distance with speed v1 and rest two third part with speed v2.find out average speed of man

Asked By: GAURAV MANSINGHANI 3 year ago
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Asked By: GAURAV MANSINGHANI 3 year ago
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Asked By: GAURAV MANSINGHANI 3 year ago
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A cylinder of radius r full of liquid of density rho is rotated about its  axis at w rad/s. What will be the increase in pressure at the centre of the cylinder ?

Asked By: SAYANTANI DATTA 4 year ago
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can the linear speed of two objects be different if they have the same angular speed?

Asked By: VIBHU GOEL 5 year ago
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Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

angular speed depends on the distance from pivot also so v may be same or different 

formula affilated is v = r ω

THE  TERMINAL SPEED ATTAINED BY AN Al  SPERE OF RADIUS 1mm  FALLING THROUGH H2O AT 200C WILL BE CLOSE TO ??

ANS 4.6 m/s

(assume laminar flow , specific gravity of Al=2.7 & η H2O =8X 10-4 PL.)

Asked By: SARIKA SHARMA 6 year ago
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Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

v = 2r2g(D-d)/9η

so v = 2(.001)2*9.8(2700-1000)/9*8*10-5

solve it 

Q IF IN THE SAME QUESTn OF BAROMETER THE ELEVATOR IS ACCELERATING UPWARD READS 76cm. THEN AIR PRESSURE IN ELEVATOR IS >76cm PLS EXPLAIN THE CONCEPT BEHIND SUCH CASES.

Asked By: SARIKA 6 year ago
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Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

when elevator will move in upward direction the extra Hg level will feel a down force and given that in movable condition it is 76 cm. Hg so really it will be more than 76 cm. 

There is some amount of water in the beaker, and a vertical  rod is passing through the centre of the circular base of the cylindrical beaker which is rotated with angular velocity ω  , then water takes a particular shape(miniscus is formed). Find the equation of the miniscus of water when the mid point of  the miniscus just touches the bottom surface of the beaker?

Asked By: AMIT DAS 6 year ago
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Answer Strategies and trick by Manish sir (it will help you to solve it by yourself)

after making the diagram, complete the miniscus as a sphere, then following conditions will be obtained

1) h = R(1-cosθ)  here h, R and θ are height of miniscus, radius of the sphere and  contact angle.

2) R = r/cosθ, r is the radius of beaker

3) tanθ = g/rw2

4) πr2hρ - πR3ρcos2θ = 2πrTcosθ

There are 4 equations, remove R, θ and T and get a relation between h and r in terms of g, w, ρ and π

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