35 - Heat and Thermodynamics Questions Answers

50gm ice at 0 degree celsius and 100gm water at 20 degree celsius are mixed, find final temperature and composition of the mixture.

Asked By: TARSH SWARNKAR
is this question helpfull: 0 0 submit your answer
Dear Sir request if you can help provide solution 
Asked By: RK GUPTA
is this question helpfull: 0 0 submit your answer
Please solve this.
Asked By: TUSHAR GUPTA
is this question helpfull: 0 0 submit your answer

6 identical rods are arranged in such a way that 3 of them make an equilateral triangle and other 3 are extended at the vertices forming a Y shape at each vertex. Name the triangle ABC ,  and other ends of rods as P, Q , R . given that temperatures at P , Q and R are 200°c,20°c and 20°c , what are temperatures at A , B , and C?

Asked By: AHAD QURESHI
is this question helpfull: 1 0 submit your answer
Joshi sir comment

A gas expands against a variable external pressure given by p = 10/V atm, where V is the volume at each stage of expansion. in expanding from 10 L to 100 L, the gas undergoes a change in internal energy ΔU = 418 J. How much heat has been absorbed?

Asked By: RICHIK BANDYOPADHYAY
is this question helpfull: 3 4 read solutions ( 1 ) | submit your answer
Joshi sir comment

process is isothermal because pV = 10 = nRT

so work done W = 2.303nRTlog(V2/V1)

so Q = Δ+ W

 

The temperature of a perfect black body

is 1000k and its area

is 0.1m2 . the heat radiated by it in 1 minute in joule is

Asked By: HASITHA.KOTTA
is this question helpfull: 6 4 submit your answer
Joshi sir comment

Q/At = σT4

now solve

A CARNOT ENGINE WORKING B/W 270 C & --1230C HAS EFFICIENCY η . IF TEMP OF SINK IS DECREASED BY 50K THE EFFICIENCY BECOMES??

ANS  4η/3

Asked By: SARIKA
is this question helpfull: 2 2 submit your answer
Joshi sir comment

according to the given condition η = 1-(150/300) = 0.5

now after decreasing temperature of sink by 50K

we get the new efficiency = 1-(100/300) = 2/3 = 4*0.5/3 = 4η/3

in a thermodynamic process on 2 moles of a monoatomic gas work done on gas is 100J & change in temp is 30 C . The change in internal energy of the gas in this process is??

Asked By: SARIKA
is this question helpfull: 2 2 submit your answer
Joshi sir comment

change in internal energy = nCvdT = 2*[R/(γ-1)]*30 = 60*8.31/[(5/3)-1] 

2 MOLES OF MONOATOMIC GAS IS MIXED WITH 1 MOLE OF A DIATOMIC  GAS. THEN γ  FOR THE MIXTURE??

ANS 1.55

Asked By: SARIKA SHARMA
is this question helpfull: 6 1 submit your answer
Joshi sir comment

total no of freedom for this mixture = (2*3+1*5)/(2+1) = 11/3

so γ = 1+[2/f] = 1 + 2/[11/3] = 1 + [6/11] = 17/11 = 1.55

a thin square plate with each side equal to 10cm , is heated by a blacksmith . the rate radiated energy by the heated plate is 1134W the temp of hot square plate is

( σ = 5.67 X 10-8 Wm2/k4 emissivity of plate =1)

ANS 1000K

Asked By: SARIKA SHARMA
is this question helpfull: 7 2 submit your answer
Joshi sir comment

according to the Stefans law P = AeσT4

so 1134 = 0.02*1*5.67*10-8*T4   (area of both the faces are considered)

so 1134*1010/11.34 = T4

so T = 1000

Login Here

Register