35 - Heat and Thermodynamics Questions Answers
50gm ice at 0 degree celsius and 100gm water at 20 degree celsius are mixed, find final temperature and composition of the mixture.
6 identical rods are arranged in such a way that 3 of them make an equilateral triangle and other 3 are extended at the vertices forming a Y shape at each vertex. Name the triangle ABC , and other ends of rods as P, Q , R . given that temperatures at P , Q and R are 200°c,20°c and 20°c , what are temperatures at A , B , and C?
A gas expands against a variable external pressure given by p = 10/V atm, where V is the volume at each stage of expansion. in expanding from 10 L to 100 L, the gas undergoes a change in internal energy ΔU = 418 J. How much heat has been absorbed?
process is isothermal because pV = 10 = nRT
so work done W = 2.303nRTlog(V2/V1)
so Q = ΔU + W
The temperature of a perfect black body
is 1000k and its area
is 0.1m2 . the heat radiated by it in 1 minute in joule is
Q/At = σT4
now solve
A CARNOT ENGINE WORKING B/W 270 C & --1230C HAS EFFICIENCY η . IF TEMP OF SINK IS DECREASED BY 50K THE EFFICIENCY BECOMES??
ANS 4η/3
according to the given condition η = 1-(150/300) = 0.5
now after decreasing temperature of sink by 50K
we get the new efficiency = 1-(100/300) = 2/3 = 4*0.5/3 = 4η/3
in a thermodynamic process on 2 moles of a monoatomic gas work done on gas is 100J & change in temp is 30 C . The change in internal energy of the gas in this process is??
change in internal energy = nCvdT = 2*[R/(γ-1)]*30 = 60*8.31/[(5/3)-1]
2 MOLES OF MONOATOMIC GAS IS MIXED WITH 1 MOLE OF A DIATOMIC GAS. THEN γ FOR THE MIXTURE??
ANS 1.55
total no of freedom for this mixture = (2*3+1*5)/(2+1) = 11/3
so γ = 1+[2/f] = 1 + 2/[11/3] = 1 + [6/11] = 17/11 = 1.55
a thin square plate with each side equal to 10cm , is heated by a blacksmith . the rate radiated energy by the heated plate is 1134W the temp of hot square plate is
( σ = 5.67 X 10-8 Wm2/k4 emissivity of plate =1)
ANS 1000K
according to the Stefans law P = AeσT4
so 1134 = 0.02*1*5.67*10-8*T4 (area of both the faces are considered)
so 1134*1010/11.34 = T4
so T = 1000