302 - Mechanics part 1 Questions Answers

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A BODY STARTS WITH INITIAL VELOCITY 30m/s & A RETARDATION OF 4m/s2 . FIND THE DISTANCE TRAVELLED BY THE BODY IN 8th SECOND.

ANS 1m

Asked By: SARIKA SHARMA
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Joshi sir comment

by v = u - at 

0 = 30 - 4t   implies t = 7.5

it means velocity will become 0 in 7.5 sec. 

distance covered in 7.5 sec. = 30*7.5 - 1/2*4*(7.5)= 225 - 225/2 = 225/2

distance covered in 7 sec. = 30*7 - 1/2*4*(7)2= 210 - 98 = 112

so distance covered in first half of eighth sec. = 112.5 - 112 = 0.5 m

distance covered in last half of eighth sec. = 0*0.5 + 1/2*4(0.5)2= 0.5

so total distance covered in eighth sec. = 0.5 + 0.5 = 1 meter

IN THE PREVIOUS QUES ( THAT WAS FROM ROTATn TOPIC , SUBMITTED 5 DAYS AGO) , I AM STILL NOT GETTING THE SOLn  SUBMITTED BY YOU.

Asked By: SARIKA SHARMA
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Joshi sir comment

if this is the question based on number of rotations then read it carefully

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A TOY CAR TRAVELS FROM A TO B AT A CONST. SPEED OF 20 km/h & IMMEDIATELY RETURNS TO A AT A CONST. SPEED v.  IF THE AVG. SPEED OF THE CAR IS 24 km/h . THEN v IS = ?

Asked By: SARIKA SHARMA
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Joshi sir comment

total distance = d+d = 2d km.

total time taken = d/20 + d/v hours

so avg. speed = 2d/[d/20 + d/v]

or 24 = 2/[1/20 + 1/v]

or 12 = 1/[1/20 + 1/v]

or 1/20 + 1/v = 1/12

or 1/v = 1/12 - 1/20

or 1/v = 2/60

or v = 30

a coin placed on a gramophone record rotating at 33rpm flies off d record , if it is placed at a dist. of more than 16cmfrom d axis of rotation . If d record is revolving at 66rpm , the coin will fly off if it is placed a distance not less than ?

ans=4cm

Asked By: SARIKA SHARMA
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Joshi sir comment

coin will fly off, if it will gain the required centrifugal

so apply mrω2 = mRW2

 

a 1 kg block is attached (& held at rest with outside support) to free end of vertically hanging spring of force const. 10Ncm-1. when block is released wat max. extensn does it cause when it comes to rest instantaneously? 

Asked By: SARIKA SHARMA
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Joshi sir comment

apply mgx = 1/2 kx2

for max. extension.

a block of mass m is suspended by a light thread from an elevator . the elevator starts moving up with a uniform acc . the work done during first t sec by tensn in thread ?

although i know how to calculate this ques . i.e w.d =Fds =m(g+a)Xds  where ds=ut+1/2(at2)  because acc is const a/c to ques BUT I want to know for ds why acc is a ,why not (a+g)

Asked By: SARIKA SHARMA
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Joshi sir comment

tension in the thread depends on g an a both. 

but displacement covered by elevator depends only on the acceleration of the elevator, it does not depend upon the acceleration g thats why we do not use g in that case for finding displacement.

remember that in the problem we have to calculate work done by tension in the thread

FROM REST A BODY ROTATE  120 rotation/min  FOR 20 sec THEN IT ROTATE FOR 5sec  WITH SAME  ROTATION . FIND  HOW MANY ROTATn IT WILL MAKE?

Asked By: SARIKA SHARMA
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Joshi sir comment

ω = ω0+ αt

so 4π = 0 + α20       so α = π/5

so total angular displacement = 1/2 π/5 202 = 40 π  = 20 rotation

and with angular velocity 2 rotation/sec total rotations in 5 sec. = 10 

so answer will be 20+10 = 30

A hunter aims his gun at a monkey sitting on a tree at the instant bullet leaves the gun the monkey drops down . WILL  THE  BULLET  HIT  THE  MONKEY  ?

Asked By: PRIYANKA DAHIYA
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Joshi sir comment

yes because monkey and bullet both are falling with the same gravity

a chain of length L and mass m lies on the surface of a smooth sphere of rad. R>L with one end tied to the top of sphere . A.find the grav.potential energy of the chain w.r.t. Centre of sphere . B.suppose the chain is released and slides down the sphere .find k.e. Of the chain when it slid through an angle @ . C.find the tangential acc. dv/dt of the chain when chain starts sliding down.
Asked By: GAURAV MAHATE
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Joshi sir comment

consider a small segment of chain at angle β from top, its length = Rdβ and mass = mRdβ/L

 

its potential energy = [mRdβ/L]gRcosβ  now integrate it within the limits 0 to L/R

for getting the answer of the second part calculate potential energy twice once between the limits 0 to L/R and then between the limits θ to θ+(L/R)

then difference of potential energy = KE of the chain. solve it ?

for getting third part differentiate v obtained in the second part with respect to t, dθ/dt will be ω and it will be v/R

finally put θ and t = 0 for getting the answer.

what is the formula for hole mobility in a semiconductor. ( not dimensional formula ,that i will find myself)

Asked By: SARIKA SHARMA
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Joshi sir comment

hole mobility  = velocity of hole/electric field applied

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