575 - Physics Questions Answers

$$\begin{gathered} Impulse is \overrightarrow{Ft} and Power = W/t \\ \overrightarrow{F}=m\overrightarrow{g} and W = mgh \\ Now calculate the time of motion \\ and get the answer \end{gathered}$$

Due to inner sphere attraction, outer sphere contracts so it is compressive stress.$$\begin{gathered} Gravitational force is G\left(\rho 4\pi R^{2}t\right)\left[\pi {(R\theta /2)}^2\right]/4R^2 \\ Outward force due to stress=S\left[2\pi \right(R\theta /2\left)t\right](\theta /2) \\ Now compare. \\ Inform for any issue and wait for video \end{gathered}$$

$$\begin{gathered} Magnetic torque = \overrightarrow{M}\times \overrightarrow{B}=i\overrightarrow{A}\times \overrightarrow{B} \\ Torque due to gravity about the point of \\ circumference = \overrightarrow{R}\times m\overrightarrow{g} \\ Now compare the two \end{gathered}$$Inform for any issue

No horizontal force.

Draw a perpendicular from centre to horizontal plane. Then calculate horizontal distance. 

Now solve. 

If any problem, then inform

$$\begin{gathered} Total flux in 6 faces =\frac{\sigma 4\pi r^2}{{\epsilon }_0} \\ so in 1 face = \frac{1}{6}\frac{\sigma 4\pi r^2}{{\epsilon }_0} \end{gathered}$$if any issue, inform

$$\begin{gathered} According to given condition \\ \frac{d\theta }{dt}=\frac{v\sin 60}{a-(v+v\cos 60)t} \\ Now solve it for t \\ then dis\tan ce = vt \end{gathered}$$solve 

inform for any difficulty

Current comes out from the surface of one sphere symmetrically 

and enters to the surface of other symmetrically.

Resistance of the medium around one sphere is

$$\begin{gathered} {\int }_r^{\infty }\frac{\rho dx}{4\pi x^2}=\frac{\rho }{4\pi }\left[-\frac{1}{x}\right] \\ on putting limits resis\tan ce around \\ one sphere =k\frac{1}{r} \\ similar for other sphere so net R_1=2\frac{k}{r} \\ In second case radius of one sphere \\ is half means r/2 \\ Thus R_2 = \frac{k}{r}+\frac{k}{r/2}=3\frac{k}{r} \\ now for same battery i_1{R}_1=i_2{R}_2 \\ solve and wait for video \end{gathered}$$