114 - Kinematics Questions Answers

Physics >> Mechanics part 1 >> Kinematics IIT JEE

A small ball is thrown from foot of a wall with minimum possible velocity to hit a bulb B on the ground at a distance L away from the wall.Find the expression for height h of shadow of the ball on the wall as a function of time t.Acceleration due to gravity is g.

Asked By: MUDIT

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Joshi sir comment

Physics >> Mechanics part 1 >> Kinematics IIT JEE

While making this paper, I stayed up till late at night working with candle light. I had two

candles of equal length L lit and placed at the same time, as shown in the figure. Immediately

thereafter I noticed that the shadow of the first candle on the left wall is not changing in

length, and the shadow of the second candle on the right wall is being shortened at a speed v.

(Take d1

= 10 cm, d2

= 20 cm, d3

= 30 cm, v = 1 mm/s, L = 20 cm.)

Asked By: AAYUSH MALAVIYA

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Joshi sir comment

Problem is interesting yet not complete. Complete it to get answer

thanks

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Two boys enter a running escalator at the ground floor of a shopping mall . The first boy repeatedly follows a cycle of p1=1 step up and then q1=2 steps down whereas the second boy repeatedly follows a cycle of p2=2 steps up and then q2=1 step down. Both of them move relative to escalator with a speed v=50cm/s . If the boys take t1=250s and t2=50s respectively to reach the first floor in complete number of cycles, how fast is the escalator running ?

Asked By: JATIN KUMAR

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Joshi sir comment

$l e t u a n d v a r e t h e s p e e d s o f b o y a n d e s c a l a t o r a c c o r d i n g t o g i v e n c o n d i t i o n [1 (u + v) T - 2 (u - v) T] n_{1} = [2 (u + v) T - 1 (u - v) T] n_{2} \Rightarrow [1 (u + v) - 2 (u - v)] T n_{1} = [2 (u + v) - 1 (u - v)] T n_{2} G i v e n t h a t T n_{1} = 250 a n d T n_{2} = 50 \Rightarrow [1 (u + v) - 2 (u - v)] 250 = [2 (u + v) - 1 (u - v)] 50 n o w s o l v e i t f o r v, u i s g i v e n$

Physics >> Mechanics part 1 >> Kinematics IIT JEE

A particle projected from the ground passes two points , which are at height 12m and 18m above the ground and a distance d=10m apart . What could be the minimum speed of projection. Acceleration due to gravity is g=10m/s^2 .

Asked By: JATIN KUMAR

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Joshi sir comment

Physics >> Mechanics part 1 >> Kinematics IIT JEE

Sir along with the written question, can you also calculate the velocity of the midpoint of CD( marked in green) under the same conditions as in question? Thank you

Asked By: DARIUS

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Solution by Joshi sir

Physics >> Mechanics part 1 >> Kinematics IIT JEE

it

Asked By: FURQAAN

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Joshi sir comment

Physics >> Mechanics part 1 >> Kinematics Medical Exam

the min no. of non coplanar and non zero vectors of unequal magnitude which can give zero resultant is _________??

Asked By: SARIKA

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Joshi sir comment

four

let three are i, j, k then fourth will be -(i+j+k)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

if y= 50 / [(x-5)² +5]² then maximum value of y will be??

Asked By: SARIKA

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Joshi sir comment

let z = [(x-5)² +5]

then dz/dx = 2(x-5)

compare it to 0 we get x = 5

so for x = 5, z will be minimum and so y will be max for that x

put x= 5 and get answer

Physics >> Mechanics part 1 >> Kinematics Board Exam

A particle has initial velocity of y = 3i+ 4j and a constant force F = 4i -3j acts on it. Then what will be the path followed by the particle?

Asked By: VIKRAM

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Joshi sir comment

acceleration is constant and initial velocity is perpendicular to it because dot product of two given vectors is 0 so this is the case equivalent to a particle thriwn from the top of a building horizontally under gravity so path will be parabolic

if you want the equation of path then reply

Physics >> Mechanics part 1 >> Kinematics Others

A ball is dropped from the top of the tower of height h. It covers a distance h/2 in the last second of its motion. How long does the ball remain in air?

Asked By: GAUTAM SAGAR

is this question helpfull: 4 2 read solutions ( 1 ) | submit your answer

Joshi sir comment

let total time of flight = t

so h = gt²/2 and

h/2 = gt-(g/2)

so gt²/4 = gt-(g/2)

or t²/4 = t -(1/2)

now solve

114 - Kinematics Questions Answers

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