42 - Magnetism Questions Answers

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Olympiad

Asked By: TUSHAR GUPTA

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Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: TUSHAR GUPTA

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Physics >> Magnetism >> Electromagnetic Induction IIT JEE

Asked By: KANDUKURI ASHISH

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Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: KESHAV

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Physics >> Magnetism >> Moving charge magnetism and force in magnetic field IIT JEE

Asked By: LUFFY

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$M a g n e t i c t o r q u e = \vec{M} \times \vec{B} = i \vec{A} \times \vec{B} T o r q u e d u e t o g r a v i t y a b o u t t h e p o i n t o f c i r c u m f e r e n c e = \vec{R} \times m \vec{g} N o w c o m p a r e t h e t w o$ Inform for any issue

Physics >> Magnetism >> Electromagnetic Induction IIT JEE

Asked By: AYUSH PAINE

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Physics >> Magnetism >> Electromagnetic Induction IIT JEE

SIR ANSWER IS given as C could u pls explain?

Asked By: AYUSH PAINE

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Physics >> Magnetism >> Alternating Current IIT JEE

SIR the answer is given only D could you pls explain

Asked By: AYUSH PAINE

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$X_{C} = 50 Ω a n d X_{L} = 100 Ω a r e i n p a r a l l e l . R e s u l \tan t i s 100 Ω c a p a c i \tan c e . N o w 100 Ω c a p a c i \tan c e a n d 100 Ω i n d u c \tan c e g i v e r e a c \tan c e 0 Ω a n d r e s i s \tan c e i s 100 Ω . S o o n l y o p t i o n D i s c o r r e c t .$

Physics >> Magnetism >> Electromagnetic Induction IIT JEE

Two Magnets of M magnetic dipole moment are placed shown in figure. What will be the intensity of magnetism at the point P shown in figure.

Asked By: BONEY HAVELIWALA

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the resultant dipole moment is √2M thus the resultant magnetic field is μ2√2M/4πd³ (ans)

Physics >> Magnetism >> Moving charge magnetism and force in magnetic field Board Exam

CALCULATE THE MAGNETIC FIELD AT THE CENTRE OF SQUARE WIRE OF SIDE (2)^1/2cm AND CARRYING A CURRENT OF 10A.?

Asked By: GAUTAM SAGAR

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Joshi sir comment

method given by BONEY is correct but formula is not correct

it should be B = 4×{ (μ₀I) / 4πR } × [sinθ₁+ Sinθ₂]

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