302 - Mechanics part 1 Questions Answers
Q.On a spring balance,
(i)10N force is applied on both the ends
(ii)10N force is applied on one end & no force on the other end.
(iii)10N is applied on one end and 20N is applied at the other.
Calculate the reading of the spring balance in each case.
Please reply fast.
i) 10 N
ii) 0 N, and it will be accelerated
iii) 10 N, and it will be accelerated
Sir,
please explain in detail how friction helps in walking?Please involve all the action and reaction forces involved in the process..Also what is the reason that we can't walk on a frictionless surface?
in accelerated motion friction will be forward and due to the same reason we take small steps when we walk in ice due to reduce friction. Without friction you can not accelerate or retard on the surface.
A body is projected with a velocity 'u' making an angle α with the horizontal. Its velocity when it is perpendicular to the initial velocity vector is:
A. ucotα B. utanα C. usinα D. ucosα
component of gravity perpendicular to the final direction is gsinθ so by equation
v=u+at
0 = u -gsinθt
so t = u/gsinθ
now along final direction v = 0+gcosθt on putting the value of t we get v = gcosθu/gsinθ = ucotθ
Due to gravity a freely falling body covers the distances in the ratio 1:3:5:7:9..............................so
if a particle passes at the same point twice (2nd and 4th sec), then it will be at heightest pont in 3rd sec. so height = 5+15+25 = 45 meter
what is projectile motion?
A particle thrown in such a way that velocity and acceleration makes variable angle with each other.
In some cases angle can be fixed
is its force dat depends on acceleratn or its acceleratn that depends upon force??
both are proportional to each other
1>What is the distance covered by a point object projected with velocity "U" making an angle theta with the horizental?
formula for calculating distance of a curve is ∫ds
where ds2 = dx2 + dy2
and equation of projectile is
y = xtanθ-(1/2)(gx2/u2cos2θ)
try to solve
if not solved give qurey i will give the complete solution
A motorboat going downstream, passes a raft at point 'A'.t = 60 min later it turned back and after some time it passes the same raft at a distance of 6 k.m. from point 'A' . find the flow velocity assuming the duty of the engine to be constant.
you can see video in you tube for this irodov problem 1.1
a body is projected at 40m/s from the horizontal ground at an angle 60 degree with the vertical. time at which it is moving perpendicular to its direction of motion is
when particle will move perpendicular to its initial direction its velocity in its ititial direction will become 0. and component of gravity in that direction = gsin30
30 degree will be the angle of motion of particle from horizontal.
now use v = u + at, 
a particle is projected at an angle of 60 degree with the horizontal at a speed of 30m/s. the time after which the speed of the particle remain half of the initial speed is
intial speed = 30 m/s
at top point speed = 30 cos60 = 15
so answer will bo half time of flight
intial speed = 30 m/s
at top point horizontal speed = 30 cos60 = 15
vertical component will be 0
so speed = 15 m/s
so answer will bo half time of flight
= usinθ/g