575 - Physics Questions Answers

in a general way the statement is correct

use kirchhoff laws

4-10i+1-30x = 0

1-30x+20(i-x) = 0

solve it for i and x

potential across A and B = 4-10i+1 = 30x

the resultant dipole moment is √2M  thus  the resultant magnetic  field is  μ2√2M/4πd³   (ans)

since the circuit is symmetrical with respect to the line given so V, the potentials at the given points will be same 

now calculate the eq. for the half circuit and double it for getting the eq. of the whole circuit

since the circuit is symmetrical with respect to the line given so V, the potentials at the given points will be same 

now calculate the eq. for the half circuit and double it for getting the eq. of the whole circuit

for one side eq. of 2 and 4 = 4/3

and then 4 in series of it so 4/3 + 4 = 16/3

finally 16/3||4/3 

eq = 16/15

final answer = 16/15 * 2 = 32/15 

current on both the resistances will be same

so V₁/R₁ = V₂/R₂

5/20000 = 105/R

solve

four

let three are i, j, k then fourth will be -(i+j+k)

let z = [(x-5)² +5]

then dz/dx = 2(x-5)

compare it to 0 we get x = 5

so for x = 5, z will be minimum and so y will be max for that x

put x= 5 and get answer 

method given by BONEY is correct but formula is not correct

it should be B = 4×{ (μ₀I) / 4πR } × [sinθ₁+ Sinθ₂]

m = z₁q₁ = z₂q₂ (1)

and q = q₁ + q₂

now solve

the resultant dipole moment is √2M  thus  the resultant magnetic  field is  μ2√2M/4πd³   (ans)

this answer is given by sarika and is correct answer