575 - Physics Questions Answers
Due to gravity a freely falling body covers the distances in the ratio 1:3:5:7:9..............................so
if a particle passes at the same point twice (2nd and 4th sec), then it will be at heightest pont in 3rd sec. so height = 5+15+25 = 45 meter
what is projectile motion?
A particle thrown in such a way that velocity and acceleration makes variable angle with each other.
In some cases angle can be fixed
what is defination of polarization
Polarisation is the phenomenon to turn light in a particular direction by any means
is its force dat depends on acceleratn or its acceleratn that depends upon force??
both are proportional to each other
1>What is the distance covered by a point object projected with velocity "U" making an angle theta with the horizental?
formula for calculating distance of a curve is ∫ds
where ds2 = dx2 + dy2
and equation of projectile is
y = xtanθ-(1/2)(gx2/u2cos2θ)
try to solve
if not solved give qurey i will give the complete solution
for an aperture of size a illuminated by a parallel beam of light having wavelength λ the fresnel distance is
ans a^2/λ what is fresnel dist.??
fringe width β = λD/d
for β = d , D is called fresnel distance
so d2 = λD
so D = d2/ λ
now change d by a
which physical quantity has its unit as LUX??
its illuminance
A motorboat going downstream, passes a raft at point 'A'.t = 60 min later it turned back and after some time it passes the same raft at a distance of 6 k.m. from point 'A' . find the flow velocity assuming the duty of the engine to be constant.
you can see video in you tube for this irodov problem 1.1
a body is projected at 40m/s from the horizontal ground at an angle 60 degree with the vertical. time at which it is moving perpendicular to its direction of motion is
when particle will move perpendicular to its initial direction its velocity in its ititial direction will become 0. and component of gravity in that direction = gsin30
30 degree will be the angle of motion of particle from horizontal.
now use v = u + at, 
a particle is projected at an angle of 60 degree with the horizontal at a speed of 30m/s. the time after which the speed of the particle remain half of the initial speed is
intial speed = 30 m/s
at top point speed = 30 cos60 = 15
so answer will bo half time of flight
intial speed = 30 m/s
at top point horizontal speed = 30 cos60 = 15
vertical component will be 0
so speed = 15 m/s
so answer will bo half time of flight
= usinθ/g