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Physics >> Mechanics part 1 >> Kinematics IIT JEE

A hunter aims his gun at a monkey sitting on a tree at the instant bullet leaves the gun the monkey drops down . WILL  THE  BULLET  HIT  THE  MONKEY  ?

Asked By: PRIYANKA DAHIYA
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Joshi sir comment

yes because monkey and bullet both are falling with the same gravity

Physics >> Electricity >> Capacitors IIT JEE
a capacitor consists of two metal plates each 10cm by 20cm ,they are seperated by a 2 mm thick insulator with dielectric constant 4.1and dielectric strength 6*10to power7 v/m.what minimum voltage will cause spark in capacitor.
Asked By: GAURAV MAHATE
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Joshi sir comment

V = Ed = 6* 107*0.002

Physics >> Electricity >> Electric Field and Potential IIT JEE

Find the potential difference Va - Vb between a and b ?

Asked By: AMIT DAS
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Joshi sir comment

let charge in the line of 24 volt is Q in the direction of battery and at point b, let the charges in the two lines are q and Q-q (q in the middle line)

now accoring to the Kirchhoff law

24-12 = Q/1 + q/2

and 24-6 = Q/1 + (Q-q)/4 

solve these 2 for q and Q 

then by point potential rules get the answer.

Physics >> Mechanics part 1 >> Work, Energy and Power IIT JEE
a chain of length L and mass m lies on the surface of a smooth sphere of rad. R>L with one end tied to the top of sphere . A.find the grav.potential energy of the chain w.r.t. Centre of sphere . B.suppose the chain is released and slides down the sphere .find k.e. Of the chain when it slid through an angle @ . C.find the tangential acc. dv/dt of the chain when chain starts sliding down.
Asked By: GAURAV MAHATE
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Joshi sir comment

consider a small segment of chain at angle β from top, its length = Rdβ and mass = mRdβ/L

 

its potential energy = [mRdβ/L]gRcosβ  now integrate it within the limits 0 to L/R

for getting the answer of the second part calculate potential energy twice once between the limits 0 to L/R and then between the limits θ to θ+(L/R)

then difference of potential energy = KE of the chain. solve it ?

for getting third part differentiate v obtained in the second part with respect to t, dθ/dt will be ω and it will be v/R

finally put θ and t = 0 for getting the answer.

Physics >> Mechanics Part 2 >> Fluid at rest Medical Exam

my previous ques from fluid topic is not solved yet so pls reply that ques & that of chem of some other one 

Asked By: SARIKA SHARMA
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Joshi sir comment

very soon you will get the answers

Physics >> Mechanics part 1 >> Dimensional Analysis Medical Exam

what is the formula for hole mobility in a semiconductor. ( not dimensional formula ,that i will find myself)

Asked By: SARIKA SHARMA
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Joshi sir comment

hole mobility  = velocity of hole/electric field applied

Physics >> Electricity >> Electric Field and Potential IIT JEE

two point charge are placed on x axis a 2mc charge at x=10 and -1 mc at x =40cm calculate the potential at pt x =100cm

Asked By: SHUBHAM SHARMA
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Joshi sir comment

potential at 100 cm = k 2 * 10-3 / 0.9 - k 1* 10-3 / 0.6

now solve   

Physics >> Heat and Thermodynamics >> Thermodynamics Medical Exam

IN THE PREVIOUS QUES P2V3 =K BUT SORRY I AM NOT GETTING HOW PV3/2 =K

Asked By: SARIKA SHARMA
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Joshi sir comment

take square root on both the sides

Physics >> Heat and Thermodynamics >> Thermodynamics Medical Exam

DURING AN ADIABATIC PROCESS IF THE PRESSURE OF AN IDEAL GAS IS PROPTIONAL TO THE CUBE OF ITS ABSOLUTE TEMP. THEN RATIO OF SPECIFIC HEATS AT CONSTANT PRESSURE & AT CONST. VOL IS?

ANS 3/2

Asked By: SARIKA SHARMA
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Joshi sir comment

P  α   T3

so P α  (PV)3

so P2V3 = K

or PV3/2 = K

so on the basis of PVγ  =  K  calculate  γ

 

Physics >> Mechanics Part 2 >> Fluid at rest Medical Exam

A SUBMERGED BLOCK RISES BY 2cm WHEN MASS OF 10kg IS REMOVED ( BE4 THAT 10kg MASS WAS KEPT ON IT)

WHAT WILL BE THE VOLUME OF THE BLOCK

Asked By: SARIKA SHARMA
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Joshi sir comment

According to the given conditions 

in first case block is completely inside water by putting 10 kg in it means density of block will be less than that of water

according to the law of floatation we know that 

wt. of solid = upthrust

so 10g + AL(0.01)Dg = AL(0.01)dg

in second case

AL(0.01)Dg = A[L-2](0.01)dg

substracting 2nd eq. by 1st eq. we will get A = 1/2

now initial lenght in start is not provided by you, if it is given then calculate V = AL(0.01)

In thid question d and D are densities of liquid and solid, A and L are area of bottom of block and its length in cm.   0.01 is for converting cm. into m.

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