575 - Physics Questions Answers
WEIGHT OF A BODY ON SURFACE OF EARTH DEPENDS UPON D ANGULAR SPEED OF ROTATn OF EARTH ABOUT ITS OWN AXIS. IS THIS STATMENT IS CORRECT? PLS. GIVE REASON ALSO
since a cetrifugal force works on the body and this force depends on angular speed so statement is correct.
IN D QUES OF RED ROSE IN WHICH WE HAVE TO FIND COLOR WHY THE COMPLEMENT COLOR OF BLUE i.e ORANGE &RED WILL B SEEN
since only blue light is present so any other colour can not be the answer
formatn of rain drop is/r involved
1)saturatn of vapour pressure
2) temp.
3)viscosity
4) surface tension
MORE THAN ONE OPTn IS/R CORRECT
saturation of V P, because due to this drops will be created.
and surface tension cause for the shape of drop
QUES TWO IDENTICAL SOUNDS s1 &s2 reach at a point P in phase. resultant loudness at a point P is ndB higher than loudness of s1 the value of n =?
ANS) 6
Let intensity of one source = I
then intensity at a point where two waves meet in phase = I+I+2√I√Icos0 = 4I
now loudness = 10logI/I0 due to a single source
and loudness at the point where 2 waves meet in phase = 10log4I/I0 = 10logI/I0+ 10log4
since 10log4 = 6 so increment = 6
IN THAT QUES OF CENTRE OF MASS BOTH THE OPTION ARE GIVEN THEN IN EXAM HOW WE KNOW THAT WHICH ONE IS CORRECT. AS WE USE Vm /M+m =V OF PLANK & m= mass of man
I could not understand, what the question is,
THE MAXm TENn IN STRING OF A SIMPLE PENDULUM IS 1.2TIMES THE MINm TENSION. IF a IS ANGULAR AMPLITUDE THEN a WILL BE
A)cos-1(4/5)
B)COS-1(3/4)
C)cos-1(15/16)
d) cos-1(7/8)
max tension at bottom point = mg+mv2/r
min tension at extreme point = mgcosθ
according to the given condition mg+mv2/r = 1.2mgcosθ (1)
and by energy conservation 1/2mv2 = mg(r-rcosθ) (2)
solve now answer will be C
A RED ROSE IS KEPT IN BLUE LIGHT. WHAT COLOUR OF ROSE WILL BE SEEN?
Since it is red rose it means it will absorb all colours other than red so in blue light it will be seen as black.
if more air is pushed in soap bubble the pressure in it decreases WHY?
since inside soap bubble pressure is given by the formula P0 + 4T/R and on pushing air R will increase so pressure will decrease.
IN THE PREVIOUS QUESn THAT WAS BALL IS DROPPED FROM HEIGHT 5M ACC. DUE TO GRAVITY IS NOT KNOWN & WE HAVE TO FIND = IT LOSES ITS VEL. BY WHICH FACTOR WHEN IT RISES TO 1.8M
IN THE SOLn SUBMITTED BY SOMEONE HE HAS TAKEN ACC. WHILE FINDING VEL EQN= =V2-U2=2AS AS CONST. SO I WANT TO KNOW WHY IN THIS QUES ACC. IS TAKEN CONST. WHILE THERE IS NO MENTn IN QUES
answer by Nikhil is correct
consider once agian
a small block of mass m is kept on a rough inclined surface of inclination o * fixed in an elevator the elevator goes up with a uniform velocity v &block doesn't slide on the wedge the w.d by the force of fricition on block in t time is?
ANS) mgtsin2o*
work done by the force of fricition on block in t time = fvtcos(90-θ) = mgsinθvtsinθ 