575 - Physics Questions Answers

why is electric field of earth is in order of 100v/m any reason by formulae

Asked By: ABHISHEK JAIN
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Joshi sir comment

emf generated between the extremes of equator line = vBl = RωBl

so E = RωBl/l = RωB = 2πRB/T 

now calculate

please,  write tibs about tidal effect  and it's fourmula ?   Is it depend inversly on the cube of the distance? and is  tidal effect of the moon's pull grater than the tidal effect of Sun?

 

Asked By: SHUBHAM VED
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Joshi sir comment

 

The tidal force is a secondary effect of the force of gravity and is responsible for the tides. It arises because the gravitational force per unit mass exerted on one body by a second body is not constant across its diameter, the side nearest to the second being more attracted by it than the side farther away. Stated differently, the tidal force is a differential force. Consider three things being pulled by the moon: the oceans nearest the moon, the solid earth, and the oceans farthest from the moon. The moon pulls on the solid earth, but it pulls harder on the near oceans, so they approach the moon more causing a high tide; and the moon pulls least of all on the far oceans (on the other side of the planet), so they stay behind more, causing another high tide at the same time. If we imagine looking at the Earth from space, we see that the whole Earth was pulled, but the near oceans more and the far oceans less; the far oceans stayed behind since they are pulled less (since they are farther away).

 

Tidal effects become particularly pronounced near small bodies of high mass, such as neutron stars or black holes, where they are responsible for the "spaghettification" of infalling matter. Tidal forces create the oceanic tide of Earth's oceans, where the attracting bodies are the Moon and, to a lesser extent, the Sun.

 

Formula

\vec a_t(axial)  ~ \approx ~ \pm ~ \hat r ~ 2 \Delta r ~ G ~ \frac{M}{R^3}

why the direction of electric dipole moment is from -ve to +ve

Asked By: HIMANSHU MITTAL
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Joshi sir comment

It is the direction of electric field due to a dipole at axial point.

 a hollow sphere of mass M (in K.G.) radius R (in m.)  is rotating with angular  frequency  omega(in radsec)  . it suddenly stops rotating and 75% of  the K.E. converted  into heat energy .   if S joulekg-kelvin is the spesific heat of material of the sphere, the rise of temperature of the sphere is ?

Asked By: SHUBHAM VED
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Joshi sir comment

Rotational K. E. = 1/2 I ω2

so 0.75 [1/2 I ω2] = M S dT

and I = 2/3 M R2

now solve

2 comparable masses m1 and m2  r orbiting about their bodycenter o at distance r1 and r2 from  their  body center respectively  with a common period T. the squar of time period  ?

Asked By: SHUBHAM VED
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Joshi sir comment

 

According to the diagram 

Gm1m2/(r1+r2)2 = m1r1ω2 = m2r2ω2

compare first part with either second or third part of the given equation for getting ω2 then find T2

how can we calculate ratio of intensities of two sound waves  having unequal amplitudes (one having double the amplitude of the other - both are sinusodial waves) and the graph is displacement vs time . 

Asked By: AMIT DAS
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Joshi sir comment

Intensity of a wave depends on two power of amplitude and two power of frequency. Check the graph carefully for getting idea about frequency and details of amplitude are given in the question.

The activity of a freshly prepared  radioactive sample is 10^10 disintegrations per second, whose mean life is 10^9 sec.

The mass of an atom of this radioisotope is 10 ^ -25 kg.  The mass (in mg) of the radioactive sample is

 

Asked By: NITIN RAO
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Joshi sir comment

dN/dt = -λN

1010 = -[1/109] N                                               λ = 1/mean life

so N = 1019 disintegration

so mass of radioisotope = 1019 *10-25 = 10-6 Kg = 1 mg

A transparent sheet of paper of refractive index 'n' and thickness 't' is pasted on one of the slits in YDSE  which uses monochromatic light of wavelength  'x'  . How many fringes will cross through the centre if the paper is removed ?

Asked By: NITIN RAO
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Joshi sir comment

total path difference created by the paper = (n-1)t

geometrical path difference = yd/D

so position of central maxima will be obtained by eq. (n-1)t  = yd/D

here y is position of central bright, d is slit appeture and D is distance between slits and screen.

so y = (n-1)tD/d

width of maxima = xD/d ,                 x is wavelength of light

so no. of fringes shifted = [(n-1)tD/d]/[xD/d] = (n-1)t/x

we taken a equal length of wire like copper and  maganim which one is more thicker ?

Asked By: VIKRANT KUMAR
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Joshi sir comment

length are equal and metals are different 

but none of the two is a deciding factor for the thickness of wire, so question is irrelevent

why current is not flow in insultor  give me proper reasion and its funtions ?

Asked By: VIKRANT KUMAR
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Joshi sir comment

 

This can be explain by using band theory.

According to this theory movable electrons are present in valence band but for conduction their transfer to conduction band (far from the nucleus in comparison to valence band) is compulsory. In insulators the gap between valence and conduction band is large thats why tranfer is not possible so no conduction

 

 

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